1896 Rhode Island gubernatorial election

The 1896 Rhode Island gubernatorial election was held on April 1, 1896. Incumbent Republican Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.40% of the vote.

Candidates
Major party candidates
 * Charles W. Lippitt, Republican
 * George L. Littlefield, Democratic

Other candidates
 * Thomas H. Peabody, Prohibition
 * Edward W. Theinert, Socialist Labor
 * Henry A. Burlingame, People's