1967 CONCACAF Championship qualification

For the 1967 CONCACAF Championship, a total of 10 teams entered the competition. , as the hosts, and 🇲🇽 mexico, as the defending champions, qualified automatically, leaving 4 spots open for competition. The 8 teams were divided into 2 groups in which the top 2 in each group advanced to the final tournament.

Group 1
Played in Kingston, Jamaica.

The group was also referred to as the Red Stripe Trophy within Jamaica. The group was sponsored by Desnoes & Geddes, the brewery of Red Stripe beer.

Haiti and Trinidad and Tobago qualified for the final tournament.

Team of the Tournament
An ideal XI for the Caribbean qualifying group was selected by The Gleaner.

Group 2
Played in Ciudad de Guatemala, Guatemala.

El Salvador and Costa Rica withdrew after disagreements with the Guatemalan federation (organizer of the tournament) due to discrepancies with the economic amounts to be distributed. CONCACAF sanctioned both federations of Costa Rica and El Salvador with a fine and a one-year suspension.

Guatemala and Nicaragua qualified for the final tournament.

Teams Qualified On 1967 CONCACAF Championship

 * 🇭🇹 haiti (Group 1 winners)
 * 🇹🇹 trinidad and tobago (Group 2 runners-up)
 * 🇬🇹 guatemala (Group 2 winners)
 * 🇳🇮 nicaragua (Group 2 runners-up)