1988 Athens Trophy – Singles

Katerina Maleeva was the defending champion but did not compete that year.

Isabel Cueto won in the final 6–0, 6–1 against Laura Golarsa.

Seeds
A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.


 * 1)  Isabel Cueto (champion)
 * 2) 🇦🇹 Judith Wiesner (quarterfinals)
 * 3) 🇦🇹 Barbara Paulus (semifinals)
 * 4)  Sabrina Goleš (second round)
 * 5)  Angeliki Kanellopoulou (quarterfinals)
 * 6) 🇮🇹 Laura Garrone (first round)
 * 7)  Silke Meier (first round)
 * 8) 🇮🇹 Laura Golarsa (final)