Medcouple



In statistics, the medcouple is a robust statistic that measures the skewness of a univariate distribution. It is defined as a scaled median difference between the left and right half of a distribution. Its robustness makes it suitable for identifying outliers in adjusted boxplots. Ordinary box plots do not fare well with skew distributions, since they label the longer unsymmetrical tails as outliers. Using the medcouple, the whiskers of a boxplot can be adjusted for skew distributions and thus have a more accurate identification of outliers for non-symmetrical distributions.

As a kind of order statistic, the medcouple belongs to the class of incomplete generalised L-statistics. Like the ordinary median or mean, the medcouple is a nonparametric statistic, thus it can be computed for any distribution.

Definition
The following description uses zero-based indexing in order to harmonise with the indexing in many programming languages.

Let $$X := \{x_0 \geq x_1 \geq \ldots \geq x_{n-1}\}$$ be an ordered sample of size $$n$$, and let $$x_m$$ be the median of $$X$$. Define the sets
 * $$X^+ := \{x_i ~|~ x_i \geq x_m \}$$,
 * $$X^- := \{x_j ~|~ x_j \leq x_m \}$$,

of sizes $$p := |X^+|$$ and $$q := |X^-|$$ respectively. For $$x_i^+ \in X^+$$ and $$x_j^- \in X^-$$, we define the kernel function
 * $$h(x_i^+, x_j^-) := \begin{cases}

\displaystyle\frac{(x_i^+ - x_m) - (x_m - x_j^-)}{x_i^+ - x_j^-} & \text { if } x_i^+ > x_j^-, \\ \operatorname{signum} (p - 1 - i - j) & \text{ if } x_i^+ = x_m = x_j^-, \end{cases}$$ where $$\operatorname{signum}$$ is the sign function.

The medcouple is then the median of the set
 * $$ \{h(x_i^+, x_j^-) ~|~ x_i^+ \in X^+ \text{ and } x_j^- \in X^- \}$$.

In other words, we split the distribution into all values greater or equal to the median and all values less than or equal to the median. We define a kernel function whose first variable is over the $$p$$ greater values and whose second variable is over the $$q$$ lesser values. For the special case of values tied to the median, we define the kernel by the signum function. The medcouple is then the median over all $$pq$$ values of $$h(x_i^+, x_j^-)$$.

Since the medcouple is not a median applied to all $$(x_i, x_j)$$ couples, but only to those for which $$x_i^+ \geq x_m \geq x_j^-$$, it belongs to the class of incomplete generalised L-statistics.

Properties of the medcouple
The medcouple has a number of desirable properties. A few of them are directly inherited from the kernel function.

The medcouple kernel
We make the following observations about the kernel function $$h(x_i^+, x_j^-)$$:


 * 1) The kernel function is location-invariant.  If we add or subtract any value to each element of the sample $$X$$, the corresponding values of the kernel function do not change.
 * 2) The kernel function is scale-invariant.  Equally scaling all elements of the sample $$X$$ does not alter the values of the kernel function.

These properties are in turn inherited by the medcouple. Thus, the medcouple is independent of the mean and standard deviation of a distribution, a desirable property for measuring skewness. For ease of computation, these properties enable us to define the two sets
 * $$Z^+ := \left.\left\{\frac{x_i^+ - x_m}{r} ~\right|~ x_i^+ \in X^+\right\}$$
 * $$Z^- := \left.\left\{\frac{x_j^- - x_m}{r} ~\right|~ x_j^- \in X^-\right\}$$

where $$r = 2 \max_{0 \leq i \leq n-1} |x_i| $$. This makes the set $$Z := Z^+ \cup Z^-$$ have range of at most 1, median 0, and keep the same medcouple as $$X$$.

For $$Z$$, the medcouple kernel reduces to
 * $$h(z_i^+, z_j^-) := \begin{cases}

\displaystyle\frac{z_i^+ + z_j^-}{z_i^+ - z_j^-} & \text { if } z_i^+ > z_j^- \\ \operatorname{signum} (p - 1 - i - j) & \text{ if } z_i^+ = 0 = z_j^- \end{cases} $$

Using the recentred and rescaled set $$Z$$ we can observe the following.


 * 1) The kernel function is between -1 and 1,  that is, $$|h(z_i^+, z_j^-)| \leq 1$$. This follows from the reverse triangle inequality $$|a| - |b| \leq |a  - b|$$ with $$a = z_i^+$$ and $$b = z_j^-$$ and the fact that $$z_i^+ \geq 0 \geq z_j^-$$.
 * 2) The medcouple kernel $$h(z_i^+, z_j^-)$$ is non-decreasing in each variable. This can be verified by the partial derivatives $$\frac{\partial h}{\partial z_i^+}$$ and $$\frac{\partial h}{\partial z_j^-}$$, both nonnegative, since $$z_i^+ \geq 0 \geq z_j^-$$.

With properties 1, 2, and 4, we can thus define the following matrix,
 * $$ H :=(h_{ij}) = (h(z_i^+, z_j^-)) =

\begin{pmatrix} h(z_0^+, z_0^-) & \cdots & h(z_0^+, z_{q - 1}^-) \\ \vdots & \ddots & \vdots \\ h(z_{p -1}^+, z_0^-) & \cdots & h(z_{p -1}^+, z_{q - 1}^-) \end{pmatrix}. $$ If we sort the sets $$Z^+$$ and $$Z^-$$ in decreasing order, then the matrix $$H$$ has sorted rows and sorted columns,
 * $$ H =

\begin{pmatrix} h(z_0^+, z_0^-)     & \geq & \cdots  & \geq & h(z_0^+, z_{q - 1}^-) \\ \geq                &      &         &      & \geq   \\ \vdots              &      & \ddots  &      & \vdots \\ \geq                &      &         &      & \geq   \\ h(z_{p -1}^+, z_0^-) & \geq & \cdots & \geq & h(z_{p -1}^+, z_{q - 1}^-) \end{pmatrix}. $$ The medcouple is then the median of this matrix with sorted rows and sorted columns. The fact that the rows and columns are sorted allows the implementation of a fast algorithm for computing the medcouple.

Robustness
The breakdown point is the number of values that a statistic can resist before it becomes meaningless, i.e. the number of arbitrarily large outliers that the data set $$X$$ may have before the value of the statistic is affected. For the medcouple, the breakdown point is 25%, since it is a median taken over the couples $$(x_i, x_j)$$ such that $$x_i \geq x_m \geq x_j$$.

Values
Like all measures of skewness, the medcouple is positive for distributions that are skewed to the right, negative for distributions skewed to the left, and zero for symmetrical distributions. In addition, the values of the medcouple are bounded by 1 in absolute value.

Algorithms for computing the medcouple
Before presenting medcouple algorithms, we recall that there exist $$O(n)$$ algorithms for the finding the median. Since the medcouple is a median, ordinary algorithms for median-finding are important.

Naïve algorithm
The naïve algorithm for computing the medcouple is slow. It proceeds in two steps. First, it constructs the medcouple matrix $$H$$ which contains all of the possible values of the medcouple kernel. In the second step, it finds the median of this matrix. Since there are $$pq \approx \frac{n^2}{4}$$ entries in the matrix in the case when all elements of the data set $$X$$ are unique, the algorithmic complexity of the naïve algorithm is $$O(n^2)$$.

More concretely, the naïve algorithm proceeds as follows. Recall that we are using zero-based indexing.

function naïve_medcouple(vector X): // X is a vector of size n. // Sorting in decreasing order can be done in-place in O(n log n) time sort_decreasing(X) xm := median(X) xscale := 2 * max(abs(X)) // Define the upper and lower centred and rescaled vectors // they inherit X's own decreasing sorting Zplus := [(x - xm)/xscale | x in X such that x >= xm] Zminus := [(x - xm)/xscale | x in X such that x <= xm] p := size(Zplus) q := size(Zminus) // Define the kernel function closing over Zplus and Zminus function h(i, j): a := Zplus[i] b := Zminus[j] if a == b:            return signum(p - 1 - i - j)         else: return (a + b) / (a - b)        endif endfunction // O(n^2) operations necessary to form this vector H := [h(i, j) | i in [0, 1, ..., p - 1] and j in [0, 1, ..., q - 1]] return median(H) endfunction

The final call to  on a vector of size $$O(n^2)$$ can be done itself in $$O(n^2)$$ operations, hence the entire naïve medcouple algorithm is of the same complexity.

Fast algorithm
The fast algorithm outperforms the naïve algorithm by exploiting the sorted nature of the medcouple matrix $$H$$. Instead of computing all entries of the matrix, the fast algorithm uses the Kth pair algorithm of Johnson & Mizoguchi.

The first stage of the fast algorithm proceeds as the naïve algorithm. We first compute the necessary ingredients for the kernel matrix, $$H = (h_{ij})$$, with sorted rows and sorted columns in decreasing order. Rather than computing all values of $$h_{ij}$$, we instead exploit the monotonicity in rows and columns, via the following observations.

Comparing a value against the kernel matrix
First, we note that we can compare any $$u$$ with all values $$h_{ij}$$ of $$H$$ in $$O(n)$$ time. For example, for determining all $$i$$ and $$j$$ such that $$h_{ij} > u$$, we have the following function:

This  function is traversing the kernel matrix from the bottom left to the top right, and returns a vector $$P$$ of indices that indicate for each row where the boundary lies between values greater than $$u$$ and those less than or equal to $$u$$. This method works because of the row-column sorted property of $$H = (h_{ij})$$. Since  computes at most $$p + q$$ values of $$h_{ij}$$, its complexity is $$O(n)$$.

Conceptually, the resulting $$P$$ vector can be visualised as establishing a boundary on the matrix as suggested by the following diagram, where the red entries are all larger than $$u$$:


 * kth-pair-greater-than.svg

The symmetric algorithm for computing the values of $$h_{ij}$$ less than $$u$$ is very similar. It instead proceeds along $$H$$ in the opposite direction, from the top right to the bottom left:

This lower boundary can be visualised like so, where the blue entries are smaller than $$u$$:


 * kth-pair-less-than.svg

For each $$i$$, we have that $$P_i \geq Q_i$$, with strict inequality occurring only for those rows that have values equal to $$u$$.

We also have that the sums
 * $$ \sum_{i=0}^{p-1} (P_i + 1) ~\qquad~ \sum_{i=0}^{p-1} Q_i$$

give, respectively, the number of elements of $$H$$ that are greater than $$u$$, and the number of elements that are greater than or equal to $$u$$. Thus this method also yields the rank of $$u$$ within the elements $$h_{ij}$$ of $$H$$.

Weighted median of row medians
The second observation is that we can use the sorted matrix structure to instantly compare any element to at least half of the entries in the matrix. For example, the median of the row medians across the entire matrix is less than the upper left quadrant in red, but greater than the lower right quadrant in blue:


 * kth-pair-middle-of-middle.svg

More generally, using the boundaries given by the $$P$$ and $$Q$$ vectors from the previous section, we can assume that after some iterations, we have pinpointed the position of the medcouple to lie between the red left boundary and the blue right boundary:


 * kth-pair-row-medians.svg

The yellow entries indicate the median of each row. If we mentally re-arrange the rows so that the medians align and ignore the discarded entries outside the boundaries,


 * kth-pair-row-medians-aligned.svg

we can select a weighted median of these medians, each entry weighted by the number of remaining entries on this row. This ensures that we can discard at least 1/4 of all remaining values no matter if we have to discard the larger values in red or the smaller values in blue:


 * kth-pair-row-medians-compared.svg

Each row median can be computed in $$O(1)$$ time, since the rows are sorted, and the weighted median can be computed in $$O(n)$$ time, using a binary search.

Kth pair algorithm
[[File:Kth pair algorithm for finding median of matrix with sorted rows and columns.gif|right|thumb|300px|A visualisation of the fast medcouple algorithm. It begins with a matrix with sorted rows and sorted columns, where darker squares are smaller than lighter squares. At each iteration, the weighted median of row medians is picked, in yellow. It is then compared to the rest of the matrix to produce candidate red upper and blue lower boundaries. The algorithm then selects the boundary which is known to exclude the global matrix median, by considering the number of entries excluded by this boundary (which is equivalent to considering the rank of the yellow entry).

The algorithm then proceeds until the yellow weighted median of row medians is exactly the medcouple, or the number of candidate entries is small enough to perform a selection sort amongst the remaining entries.]]

Putting together these two observations, the fast medcouple algorithm proceeds broadly as follows.


 * 1) Compute the necessary ingredients for the medcouple kernel function $$h(i,j)$$ with $$p$$ sorted rows and $$q$$ sorted columns.
 * 2) At each iteration, approximate the medcouple with the weighted median of the row medians.
 * 3) Compare this tentative guess to the entire matrix obtaining right and left boundary vectors $$P$$ and $$Q$$ respectively. The sum of these vectors also gives us the rank of this tentative medcouple.
 * 4) If the rank of the tentative medcouple is exactly $$pq/2$$, then stop. We have found the medcouple.
 * 5) Otherwise, discard the entries greater than or less than the tentative guess by picking either $$P$$ or $$Q$$ as the new right or left boundary, depending on which side the element of rank $$pq/2$$ is in. This step always discards at least 1/4 of all remaining entries.
 * 6) Once the number of candidate medcouples between the right and left boundaries is less than or equal to $$p$$, perform a rank selection amongst the remaining entries, such that the rank within this smaller candidate set corresponds to the $$pq/2$$ rank of the medcouple within the whole matrix.

The initial sorting in order to form the $$h(i,j)$$ function takes $$O(n \log n)$$ time. At each iteration, the weighted median takes $$O(n)$$ time, as well as the computations of the new tentative $$P$$ and $$Q$$ left and right boundaries. Since each iteration discards at least 1/4 of all remaining entries, there will be at most $$O(\log n)$$ iterations. Thus, the whole fast algorithm takes $$O(n \log n)$$ time.

Let us restate the fast algorithm in more detail.

function medcouple(vector X): // X is a vector of size n // Compute initial ingredients as for the naïve medcouple sort_decreasing(X) xm := median(X) xscale := 2 * max(abs(X)) Zplus := [(x - xm)/xscale | x in X such that x >= xm] Zminus := [(x - xm)/xscale | x in X such that x <= xm] p := size(Zplus) q := size(Zminus) function h(i, j): a := Zplus[i] b := Zminus[j] if a == b:            return signum(p - 1 - i - j)         else: return (a + b) / (a - b)        endif endfunction // Begin Kth pair algorithm (Johnson & Mizoguchi) // The initial left and right boundaries, two vectors of size p L := [0, 0, ..., 0] R := [q - 1, q - 1, ..., q - 1] // number of entries to the left of the left boundary Ltotal := 0 // number of entries to the left of the right boundary Rtotal := p*q // Since we are indexing from zero, the medcouple index is one // less than its rank. medcouple_index := floor(Rtotal / 2) // Iterate while the number of entries between the boundaries is // greater than the number of rows in the matrix. while Rtotal - Ltotal > p:        // Compute row medians and their associated weights, but skip // any rows that are already empty. middle_idx := [i | i in [0, 1, ..., p - 1] such that L[i] <= R[i]] row_medians := [h(i, floor((L[i] + R[i])/2) | i in middle_idx]        weights := [R[i] - L[i] + 1 | i in middle_idx]         WM := weighted median(row_medians, weights)         // New tentative right and left boundaries         P := greater_h(h, p, q, WM)         Q := less_h(h, p, q, WM)         Ptotal := sum(P) + size(P)         Qtotal := sum(Q)         // Determine which entries to discard, or if we've found the medcouple         if medcouple_index <= Ptotal - 1:             R := P             Rtotal := Ptotal         else:             if medcouple_index > Qtotal - 1:                 L := Q                 Ltotal := Qtotal             else:                 // Found the medcouple, rank of the weighted median equals medcouple index return WM            endif endif endwhile // Did not find the medcouple, but there are very few tentative entries remaining remaining := [h(i, j) | i in [0, 1, ..., p - 1], j in [L[i], L[i] + 1, ..., R[i]] such that L[i] <= R[i] ] // Select the medcouple by rank amongst the remaining entries medcouple := select_nth(remaining, medcouple_index - Ltotal) return medcouple endfunction

In real-world use, the algorithm also needs to account for errors arising from finite-precision floating point arithmetic. For example, the comparisons for the medcouple kernel function should be done within machine epsilon, as well as the order comparisons in the  and   functions.

Software/source code

 * The fast medcouple algorithm is implemented in R's robustbase package.
 * The fast medcouple algorithm is implemented in a C extension for Python in the Robustats Python package.
 * A GPL'ed C++ implementation of the fast algorithm, derived from the R implementation.
 * A Stata implementation of the fast algorithm.
 * An implementation of the naïve algorithm in Matlab (and hence GNU Octave).
 * The naïve algorithm is also implemented for the Python package statsmodels.