Rose Lake Township, Michigan

Rose Lake Township is a civil township of Osceola County in the U.S. state of Michigan. The population was 1,406 at the 2020 census.

Geography
According to the United States Census Bureau, the township has a total area of 34.9 sqmi, of which 33.6 sqmi is land and 1.3 sqmi (3.61%) is water.

Demographics
As of the census of 2000, there were 1,231 people, 490 households, and 365 families residing in the township. The population density was 36.6 PD/sqmi. There were 1,220 housing units at an average density of 36.3 /sqmi. The racial makeup of the township was 98.70% White, 0.08% African American, 0.32% Native American, 0.16% Asian, 0.08% Pacific Islander, 0.16% from other races, and 0.49% from two or more races. Hispanic or Latino of any race were 0.41% of the population.

There were 490 households, out of which 29.2% had children under the age of 18 living with them, 64.1% were married couples living together, 6.7% had a female householder with no husband present, and 25.5% were non-families. 19.2% of all households were made up of individuals, and 8.4% had someone living alone who was 65 years of age or older. The average household size was 2.51 and the average family size was 2.87.

In the township the population was spread out, with 23.6% under the age of 18, 8.0% from 18 to 24, 26.7% from 25 to 44, 25.1% from 45 to 64, and 16.5% who were 65 years of age or older. The median age was 40 years. For every 100 females, there were 99.2 males. For every 100 females age 18 and over, there were 95.8 males.

The median income for a household in the township was $34,667, and the median income for a family was $38,750. Males had a median income of $29,833 versus $25,234 for females. The per capita income for the township was $16,731. About 6.7% of families and 7.6% of the population were below the poverty line, including 9.0% of those under age 18 and 7.6% of those age 65 or over.