Talk:Brunt–Väisälä frequency

Untitled
Um, in the context section, it says that it can be that N^2 < 0. I'm no expert, but since none of the previous equations invoke imaginary numbers, I'm assuming that's a typo or vandalism. Consequently, I'm removing changing the N^2 to N. --Warren Platts
 * We are studying linear waves and so a complex context is assumed: N^2 < 0 means the atmosphere is convectively unstable. 131.111.17.19 (talk) 20:54, 27 July 2013 (UTC)

I don't want to tread on any toes by editing the article directly, but unless I'm very much mistaken, since $$ \rho = \rho (z) $$, the partials $$\frac{\partial \rho (z)}{\partial z}$$ should be exact: $$\frac{d \rho }{d z}$$. Jcwhitehead (talk) 23:10, 7 April 2014 (UTC)


 * I don't think that's quite right. Density rarely depends only on height. $$N$$ emerges from studying waves in stratified fluids where the partial derivative is used.Jobla6 17:25, 26 September 2019 (UTC) — Preceding unsigned comment added by Jobla6 (talk • contribs)

Symbol origin
Does anyone know why N is used as the symbol? Ohmanger (talk) 16:26, 7 January 2016 (UTC)

Derivation Incorrect
The solution to the diferential equation
 * $$\frac{\partial^2 z'}{\partial t^2} = \frac{g}{\rho_0} \frac{\partial \rho (z)}{\partial z} z' $$

should be :$$z' = w_1 e^{i \sqrt{N^2} t}\! + w_2 e^{-i \sqrt{N^2} t}\!$$, since it is a second order differential equation. We need the second constant to describe the runaway growth that is described later, which could be in either direction.

Pavan7411 (talk) 17:19, 1 September 2023 (UTC)