Talk:Differentiating Functions

Untitled
Admiral Payne 18:44, 25 October 2005 (UTC)

Okay, I edited the main article's part from f(x+dx)-f(x) -> (x+dx)^n-x^n..

Maybe this needs a little more explaining.

We had f(x+dx)-f(x) for starters. Now we filled this into f(x)=x^n, because this is the main function we want to prove. That would mean; we put (x+dx) and (x) as 'x' into f(x).. Thus leading to:

(x+dx)^n-x^n