Talk:Flash evaporation

Extensive re-write
The article seemed to be focused only on the flash evaporation of a multi-component liquid and it did not discuss the evaporation of a single-component liquid at all. Also, some of the wording was confusing. Hence, I did an extensive re-write. I will complete the multi-component section with the next day or so. - mbeychok 05:11, 7 April 2006 (UTC)


 * I just finished the complete revision and expansion of this article. - mbeychok 07:34, 8 April 2006 (UTC)

Confused
Is the fact that flash evaporators are isentropic true for both multi-component systems as well as single? What are some properties of all flash evaporators? 143.246.14.19 (talk) 18:07, 13 April 2010 (UTC)PhysicsStudent


 * Glad you brought this up, because I erred in stating that the flash evaporation of a single-component liquid is isentropic. An adiabatic process is isentropic only if the process is reversible. I have corrected the article to state that the flash evaporation of a single-component liquid is isenthalpic. answer you In any event, the equation given for a single-component liquid is correct. mbeychok (talk) 22:11, 14 April 2010 (UTC)


 * Now that I have checked the article history, I see that I originally wrote that flash evaporation of a single-component liquid was isenthalpic. The change to isentropic was made by an unregistered user on March 23, 2009. So the error was not mine after all. mbeychok (talk) 22:35, 14 April 2010 (UTC)
 * Whew, that's a relief... — Preceding unsigned comment added by 192.158.48.17 (talk) 12:42, 29 January 2015 (UTC)

Derivation of Flash Evaporation Single Component & Definition of X
Mass Balance of initial and final liquid and vapour
 * $$m_i = m_f$$
 * $$m_{l,i} = m_{v,f}+m_{l,f}$$

Adiabatic energy balance
 * $$m_{l,i} h_{l,i} = m_{v,f} h_{v,f}+m_{l,f} h_{l,f}$$


 * $$(m_{v,f}+m_{l,f}) h_{l,i} = m_{v,f} h_{v,f}+m_{l,f} h_{l,f}$$
 * $$m_{l,f} h_{l,i} + m_{v,f} h_{l,i} = m_{v,f} h_{v,f} + m_{l,f} h_{l,f}$$
 * $$m_{l,f} h_{l,i} - m_{l,f} h_{l,f} = m_{v,f} h_{v,f} - m_{v,f} h_{l,i}$$
 * $$m_{l,f} (h_{l,i} - h_{l,f}) = m_{v,f} (h_{v,f} - h_{l,i})$$


 * $$ \frac{(h_{l,i} - h_{l,f})}{(h_{v,f} - h_{l,i})} = \frac{m_{v,f}}{m_{l,f}}$$

or in articles original notation
 * $$\frac{m_{v,f}}{m_{l,f}} = \frac{H_u^L - H_d^L}{H_d^V - H_u^L}$$

The current article also suggests (from definition X = weight fraction vaporized) that X = m_vap ÷ m_total, where m_total = m_vap+m_liq, which is is the same definition as vapor quality. From the derivation, X should be defined as the 'ratio' of vaporised mass to remaining liquid.
 * $$X = \frac{m_{v,f}}{m_{l,f}}$$ — Preceding unsigned comment added by RedHotIceCube (talk • contribs) 14:15, 22 October 2015 (UTC)

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