Talk:Gaseous diffusion

Older comments
In the Technology section, does this sentence: "This process is based on the principle that in a closed box, all molecules have the same energy; therefore the lighter molecules, on average, travel faster than the heavier molecules." need to be explained? I don't understand the logical connector 'therefore'. If all molecules have the same energy, why would the lighter molecules, on average, travel faster than the heavier ones?--Rvanden (talk) 16:37, 7 April 2009 (UTC)


 * It doesn't really ring true anyway. I would expect that in such a closed box there would be a well defined range of energies. In this case it would still be true that lighter molecules on average would travel faster than heavier molecules, on the assumption that they would all have the same average energy. To say they all have the same energy seems like an oversimplification to me to make calculation easier. This is what the physics of the situation tells me anyway. Anyway to answer your question if a light molecule and a heavy molecule share the same energy, the lighter molecule would necessarily move faster - a straight result of kinetic energy. Soarhead77 (talk) 13:13, 16 August 2009 (UTC)

standard practices
In the Technology Section "The gas leaving the container is somewhat enriched in the lighter molecules, while the residual gas is somewhat depleted." should read "The gas leaving the container is somewhat depleted in the heavier molecule, while the residual gas is somewhat enriched." In isotope chemistry, common practice is to always to refer enrichment or depletion with regards to the heavier isotope not the lighter.

Jeepxjbodo (talk) 23:45, 27 October 2009 (UTC)

Effusion?
Doesn't this sound like effusion?

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