Talk:Gyroelongated triangular bicupola

Volume
The volume formula shown appears to me to be equivalent to
 * $$ \frac{\sqrt{2}}{3} (5+3\sqrt{1+\sqrt{3}}) a^3 $$

(Strange that WolframCo didn't simplify it.) Any objection to using the simpler form? —Tamfang (talk) 05:12, 1 August 2010 (UTC)


 * Or better yet : $$ \sqrt{2} (\frac{5}{3}+\sqrt{1+\sqrt{3}}) a^3 $$. I've confirmed the equivalence with Sage.
 * And yet adding up the volumes given in Cuboctahedron and Antiprism I get $$ 6+2\sqrt{3}+\sqrt{2}+2\sqrt(1+\sqrt{3})$$. —Tamfang (talk) 18:02, 17 June 2012 (UTC)