Talk:Limit set

Dubious claim about alpha-limit set
FYI. This article was copied from PlanetMath but appears to contain a rather dubious definition of the alpha-limit set. In general, f is not a bijection, so $$f^{-1}$$ as an inverse doesn't exist. However, it is common in dynamical systems for $$f^{-1}$$ to denote the preimage. However, I think its rather glib to define the alpha-limit set as the set of preimages... that would certainly make the alpha-limit set a much more complex and complicated beast than the omega-limit set. (I think it would make the alpha-limit set be a Julia set). Needs clarification. linas 14:22, 9 June 2006 (UTC)


 * Never mind. If f is restricted to be a homeomorphism, then its a bijection, and that takes care of that. I think a more general definition of the alpha-limit set is possible, but do not wish to invent one here. linas 14:42, 10 June 2006 (UTC)

simply connected ?
" if X is compact then lim&omega; &gamma; and lim&alpha; &gamma; are nonempty, compact and simply connected"

limω could be a cycle but how is a cycle simply-connected? Novwik (talk) 08:57, 6 December 2007 (UTC)