Talk:Lucky numbers of Euler

Alternative presentation
This can be (and usually is) presented as $n^2 + n + 41$ -- is it worth adding a paragraph explaining this? --Matt Westwood 06:18, 11 April 2017 (UTC)

Yes, I think it is needed to explain. Confused me a lot, but I figured it out now: Let $f(n) = n^{2} &minus; n + 41$ and $g(n) = n^{2} + n + 41$. The relation is $f(n + 1) = g(n)$. --Lilalas (talk) 15:41, 20 April 2017 (UTC)

1 is not a lucky number of Euler
Using the given criteria, 1 should not be included because 1^2 - 1 + 1 = 1 is not a prime number. The OEIS sequence doesn't include 1, nor does Wolfram Mathworld. Travisrm89 (talk) 23:07, 3 April 2023 (UTC)