Talk:Magnetic pole strength

Current definition?
I'm not sure if this is the standard defining equation:


 * $$p = \frac{W}{I}$$

Its not clear which entity is doing work:


 * "where W is the work which has been made when the magnetic pole has been turned around the wire in a closed loop". (???...)

If the Ampere law "follows almost immediately from this", then it can only mean we need the more standard definition using the H-field:


 * $$\mathbf{H} = \frac{\mathbf{F}}{p}\quad\rightarrow\quad \mathbf{F}=p\mathbf{H} $$

meaning H is the force F on a unit pole p, analagous to electric field E as force on a unit charge q


 * $$\mathbf{E} = \frac{\mathbf{F}}{q}\quad\rightarrow\quad \mathbf{F}=q\mathbf{E} $$

so that the work done W on an electric charge due to a field E is:


 * $$W = \int \mathbf{F}\cdot d\mathbf{r} = q \int \mathbf{E}\cdot d\mathbf{r} $$,

Likewise for magenetic poles


 * $$p = \frac{1}{I}\int \mathbf{F}\cdot d\mathbf{r} = \frac{p}{I}\oint \mathbf{H}\cdot d\mathbf{r}\quad \rightarrow\quad I = \oint \mathbf{H}\cdot d\mathbf{r}$$,

in which case


 * "pole strength is the work is done on the magnetic pole around some closed path due to a field H per unit current (in a conductor, say a wire)".

Hence the current definition is redundant, though I suppose it could be mentioned as equivalent using Ampere's law, the definition of work, and the definition of p using H.

Its not sourced anyway (like everything else in the article). I have access to the one piddly book at the bottom, but we need a few more than that. F = q(E+v×B) ⇄ ∑ici 12:34, 7 April 2012 (UTC)

blank and re-direct
This page is to be blanked and re-directed to either magnetic monopoles or magnetic moment, as proposed here. F = q(E+v×B) ⇄ ∑ici 22:02, 7 April 2012 (UTC)