Talk:Mercer's condition

Can someone please explain how this is related to a kernel in plain simple English? Are http://en.wikipedia.org/wiki/Mercer%27s_theorem and http://en.wikipedia.org/wiki/Mercer%27s_condition are same? I am not able to understand significance of Mercer's_condition —Preceding unsigned comment added by 59.178.162.216 (talk) 09:52, 12 October 2008 (UTC)

This article is not correct
To the best of my knowledge, the kernel has to be symmetric and continuous (or measurable). This article needs attention of an expert. --64.134.26.199 (talk) 22:06, 3 September 2011 (UTC)

Lack of Explanation
Fubini may be the relevant explanation for the first equality of the last section, but it is not clear that it applies directly. In particular, note that $g(x)$ is only assumed to be in $L^2$ at this point, not in $L^1$. — Preceding unsigned comment added by 2607:EA00:104:3C00:653B:96F:A76A:CAE5 (talk) 16:10, 9 September 2014 (UTC)