Talk:Metal-mesh optical filter

Untitled
From the article:

The amplitude of both of these electric fields will be equal, and the ratio of their amplitudes is $$\Gamma(\omega)$$, where $$\Gamma$$ is the reflection coefficient, and $$\omega = g/\lambda$$ is the normalized frequency.

But of the aptitude [sic] of both are equal, then the ratio of their amplitudes will be one, so something is unclear here.

This needs review by an expert.

- Leonard G. (talk) 00:25, 4 April 2012 (UTC)