Talk:Narayana number

Some trouble with the formula ?
It seems, according to Sloane, that the formula should read

$$N(n,k)=\frac1k {n \choose {k-1}}{n-1\choose k-1}$$

ManiacParisien (talk) 12:40, 4 December 2013 (UTC)


 * That's the same, just written differently. Both expressions evaluate to
 * $$N(n,k)=\frac{n!(n-1)!}{k!(k-1)!(n-k+1)!(n-k)!} \;.$$
 * MuDavid (talk) 08:12, 9 May 2017 (UTC)