Talk:Novikov conjecture

What does $$\mathcal{L}_i(M)$$ stand for? - 69.174.134.88 21:50, 9 June 2006 (UTC)

Glaring error
We supposedly have:


 * $$f: M\rightarrow BG$$
 * $$x \in H^{n-4i} (M;\mathbb{Q} ).$$
 * $$\left\langle f^*(x) \cup L_i(M),[M] \right\rangle \in \mathbb{Q}$$

How can we take $$ f^*(x)$$? Cohomology is contravariant, so $$ f^*: H^*(BG)\rightarrow H^*(M)$$. This mistake renders the statement of the conjecture totally non-sensical.

In the linked seminar notes there ist the same mistake. I think, x should be in H^{n-4i}(BG). This makes most sense in view of how a result of Novikov is shown to be a special case of the Novikov conjecture the seminar notes, I think. --Cardano 13:09, 12 October 2006 (UTC)


 * That link (as well as the mistake) was on the original page, created a year ago. Thank you, anonymous person. And Cardano you're right - the conjecture is stated in the referreed article, page 195 at http://www.maths.ed.ac.uk/~aar/books/wall1.pdf Orthografer 15:16, 12 October 2006 (UTC)