Talk:Nuclear magneton

Suggested merger
The "Neutron magnetic moment" article seems to make sense. 173.175.54.131 (talk) 05:16, 7 July 2010 (UTC)

simple semi-Classical explanation ??
First, quarks have spin-angular-momentum of $${\hbar} \over {2}$$; typical charge of $${e} \over {3}$$; and typical mass of $${m_\mathrm{p}} \over {3}$$. Accordingly, the expected quark magneton would be:


 * $$\mu_q = {{ {{e} \over {3}}   {{\hbar} \over {2}}  } \over { 2 {{m_P} \over {3}} } }$$


 * $$= {{\mu_N} \over {2}}$$

Then, in units of $$\mu_q$$,


 * $$\mu_P \approx 6$$


 * $$\mu_N \approx -4$$

Then, assuming that


 * $$\mu_P = 2 \mu_{up} + 1 \mu_{down}$$
 * $$\mu_N = -1 \mu_{up} - 2 \mu_{down}$$

Then, that system of equations can be quickly solved, yielding


 * $$\mu_{up} = {{8} \over {3}}$$
 * $$\mu_{down} = {{2} \over {3}}$$

Then, accounting for up-quarks having twice the normal quark charge; and attributing the remaining discrepancies to differences in up-quark vs. down-quark masses,


 * $$m_{up} = {{1} \over {4}}$$
 * $$m_{down} = {{1} \over {2}}$$

in units of $$m_P$$. Thus, a simple picture, of down-quarks having twice the mass, and (negative) half the charge, of up quarks; qualitatively accounts, for proton & neutron magnetons, as well as masses (neutrons heavier than protons).66.235.38.214 (talk) 03:42, 18 October 2012 (UTC)


 * As you can find in the page for Up quark and Down quark, typical quark masses are in fact around $${m_\mathrm{p}} \over {100}$$, so this is clearly not helpful. Also, as far as I can tell this is original work and according to Wikipedia's policy should not be included on the page. Ragnarstroberg (talk) 15:28, 15 January 2013 (UTC)