Talk:Phase angle (vectors, phasors, and periodic phenomena)

Untitled
How about a picture or diagram? — Preceding unsigned comment added by Jamesalex  (talk • contribs) 06:26, 24 February 2006 (UTC)

it's nonsense
The article says:


 * The phase angle of a point on a periodic wave is the distance between the point and a specified reference point, expressed using an angular measure.

and


 * For example, in electrical engineering, sinusoidal voltage and current can be expressed as a sine function with a magnitude such as:

v(t) = V_m \cos( \omega t + \varphi ) \; $$


 * Where $$\varphi$$ is the phase angle,

How do I reconcile those two statements? What is the "reference point"? And what is "the point"? Usually the reference point is t=0, and "the point" is t. The angle at t=0 is $$\varphi,$$ and at t is $$\omega t + \varphi,$$ so the distance between them is just $$\omega t,$$ which does not depend on $$\varphi!$$

Furthermore, the article says:


 * This angular measure is obtained by projecting a rotating vector onto the real axis of the complex plane.

Using the same example, the projection on the real axis is the voltage v, not $$\varphi$$.

--Bob K 18:00, 19 August 2007 (UTC)

it is the measure of angle ,which is made by a wave in relation to plane — Preceding unsigned comment added by 117.212.52.206 (talk) 15:52, 5 September 2011 (UTC)