Talk:Q-gamma function

Unfortunately, the referenced article gives wrong formulae


 * $$ \Gamma_q(x) =[2]_{q^{\ }}^{\frac 12} \Gamma_{q^2}\left(\frac 12\right)(1-q)^{\frac 12-x}e^{\frac{\theta q^x}{1-q-q^x}}, \quad 0<\theta<1.$$


 * $$ \Gamma_{q^n}\left(\frac {x}n\right)\Gamma_{q^n}\left(\frac {x+1}n\right)\cdots\Gamma_{q^n}\left(\frac {x+n-1}n\right) =[n]_q^{\frac 12-x}\left([2]_q \Gamma^2_{q^2}\left(\frac12\right)\right)^{\frac{n-1}{2}}\Gamma_q(x).$$

It is discussed in detail in, and can be easily checked numerically.

So, I'm going to remove the incorrect formulae. VladimirReshetnikov (talk) 18:57, 30 September 2016 (UTC)