Talk:Root-mean-square speed

how does the units work out?
the units are:

v2(Distance2/Time2)=3*R(Energy/(mole*Temprature))*Temprature/Moleculare weight(mass/mole)

Energy=mass*Distance/Time2

Therefore:

v2(Distance2/Time2)=3*R( mass *Distance/Time2/( mole * Temprature ))* Temprature /Moleculare weight( mass / mole )

I am missing a duplication in the Distance...

Can someone help me? —Preceding unsigned comment added by 85.250.175.153 (talk) 21:35, 7 December 2008 (UTC)

You missed out one distance in the energy definition. Remember: E = mc2, so in SI, 1 Joule is 1 kg m2 s–2. So, kT/m has units of velocity squared. Grunkhead (talk) —Preceding undated comment added 12:33, 5 June 2009 (UTC).

Iteresting question: How can we incorperate the speed of light into these equations? This has to be the limiting value for the speed. -Anonymous If one wants to, say find the root mean square speed of particles inside of a star the speeds would probably approach very high values, which becomes an issue. — Preceding unsigned comment added by 68.73.192.73 (talk) 20:44, 3 January 2013 (UTC)