Talk:Titu's lemma

Sedrakyan's inequality in China
$$a_i,b_i>0$$

$$\begin{cases} \displaystyle \sum_{i=1}^n \frac{a_i^{m+1}}{b_i^m} \ge \frac{(\displaystyle \sum_{i=1}^n a_i)^{m+1}}{(\displaystyle \sum_{i=1}^n b_i)^m},m<-1,m>0\\ \displaystyle \sum_{i=1}^n \frac{a_i^{m+1}}{b_i^m} \le \frac{(\displaystyle \sum_{i=1}^n a_i)^{m+1}}{(\displaystyle \sum_{i=1}^n b_i)^m},-1<m<0 \end{cases}$$

I heard 權方和不等式 from Chinese forum and I created that page in 2014. I don't know what it calls in English. I wonder that they have different routes to the same goal. --Tttfffkkk (talk) 11:39, 9 April 2021 (UTC)

While Titu’s inequality is the more well known name for this in the U.S., it is important to give credit to the original author. This was known (and still is) as Sedrakyan’s inequality in other parts of the world years before Titu’s book. 73.44.170.254 (talk) 00:57, 25 May 2024 (UTC)