Talk:Tutte polynomial

Isn't the bit about the Jones polynomial all wrong?
The current text about the hyperbola xy=1 is completely at odds with Propos 1 of [ref], which in a later example clearly states that V_{D(G)}( s ) = ( s^{-1/2} + s^{1/2} )^{|E|-|V|+1} s^{1-|E|-|V|}  T_G( s^2, (s^2+1)/(s^2-s) ).

[ref] Francois Jaeger, Tutte Polynomials and Link polynomials, Proc. Am. Math. Soc. Vol 103, No 2, June 1988 —Preceding unsigned comment added by 82.33.119.244 (talk) 18:40, 20 February 2010 (UTC)

Typesetting
The typesetting in this article needs fixing. 86.145.57.232 (talk) 11:33, 24 January 2014 (UTC)
 * Looks ok to me. What, specifically, do you see wrong? —David Eppstein (talk) 17:07, 24 January 2014 (UTC)

Wrong formula
I think this formula is wrong: $$Z(G) = 2\left(e^{-\alpha}\right)^{|E| - r(E)} \left(4 \sinh \alpha \right )^{r(E)} T_G \left (\coth \alpha, e^{2 \alpha} \right).$$ Isn't this should be $$Z(G) = \left(2e^{-\alpha}\right)^{|E| - r(E)} \cdots $$ ? 133.11.30.75 (talk) 16:27, 24 August 2014 (UTC)

Well-defined?
Why even mention well-definedness in the definition? There is no choice of representatives being made nor anyting that would potentially make the definition ambigous. Instead, I suggets it should be mentioned that the $$\sum$$ has only finitely many summands (hence indeed produces a polynomial) because the graph is finite. Or maybe this was what was meant with well-definedness in this context?--Hagman (talk) 12:02, 31 August 2014 (UTC)
 * There are several ways of defining the Tutte polynomial, for example one might start from the contraction-deletion definition. For some of these definitions there are choices, for example, the order of edges to operate on, which make it non-obvious that the answer is well-defined, in the sense of being independent of the various choices.  Starting from the Whitney rank polynomial definition makes it clear that it is well-defined, because there are no choices to make, hence the comment in the text.  Of course it is now not obvious that it is a contraction-deletion invariant.  Deltahedron (talk) 12:36, 31 August 2014 (UTC)