User:Рајко Велимировић/sandbox

$$ \pi=180.m.sin(\frac{1}{m})$$ $$180\lim_{m \to \infty}m.sin(\frac{1}{m})$$ $$180\lim_{m \to \infty}\frac{sin(\frac{1}{m})}{\frac{1}{m}}$$ $$\frac{1}{m}=t$$ $$t \rightarrow \ 0$$