User:Amit6/math-hoax1

Assume that a and b are two real numbers. Hence, (a - b)2 = a2 - 2ab + b2 or, (a - b)2 = b2 - 2ab + a2 or, (a - b)2 = (b - a)2 or, a - b = b - a or, a + a = b + b or, 2a = 2b or, a = b or, a2 = ab or, a2 - b2 = ab - b2 or, (a + b)(a - b) = b(a - b) or, a + b = b or, a + a = a or, 2a = a or, 2 = 1 !!!

$$\text{If}~a\ \text{and}~b\ \text{are two real numbers}\ \!$$

$$\begin{align} (a-b)^2 & = a^2-2ab+b^2 \\ (a-b)^2 & = b^2-2ab+a^2 \\ (a-b)^2 & = (b-a)^2 \\ a-b & = b-a \\ a+a & = b+b \\ 2a & = 2b \\ a & = b \\ a^2 & = ab \\ a^2-b^2 & = ab-b^2 \\ \left ( a+b \right ) \left ( a-b \right ) & = b \left ( a-b \right ) \\ a+b & = b \\ a+a & = a \\ 2a & = a \\ 2 & = 1 \quad {\color{red}!!!} \\ \end{align}$$