User:Aver25

$$P(n|\lambda) = \frac{\lambda^n}e^{-\lambda}$$ $$P(d(x) | i(x)) = \prod_{x}\frac{(i(x) * h(x))^{d(x)}}e^{-i(x) * h(x)}$$ $$max_{i(x)} \prod_{x}\frac{(i(x) * h(x))^{d(x)}}e^{-i(x) * h(x)} = max_{i(x)} log\prod_{x}\frac{(i(x) * h(x))^{d(x)}}e^{-i(x) * h(x)}$$ $$\sum_{x}log d(x)! + \sum_{x}d(x)log(i(x) * h(x)) - \sum_{x}(i(x) * h(x))$$