User:BertSierra/sandbox

Mathematica 8 can evaluate the integral $$ \int \frac{\sqrt{\sinh \phi }}{\theta } \, d\phi $$.

The result is $$ \frac{2 \sqrt{i \sinh (\phi )} E\left(\left.\frac{1}{4} (\pi -2 i \phi )\right|2\right)}{\theta \sqrt{\sinh (\phi )}} $$.