User:Catprog/SolarCalc

Using http://www.greenandgoldenergy.com.au/images/DirectBeamAustraliaandNewZealand.GIF (5kWh/m2/day = 1825 kWh/m2/year

From http://uic.com.au/nip37.htm (In 2003-04 Australia's power stations produced 237 billion kilowatt hours)

237,000,000,000 / 1,825 = 129.86 km2 (1,000,000 m2 in 1 km2)

assuming 10% efficency =1298.63 km2

20-21 km wide circle, .0169 % total area of australia

assuming 100% efficency =129.86 km2

6-7 km wide circle, .00169 % total area of australia

using projected (http://www.eia.doe.gov/oiaf/ieo/world.html) worldwide energy use in 2015 is 162,068,301,805,239 kilowatt hours (per year)

690 times the energy

10% efficency = 11.660% the area of australia, 896,054.70km2 , 534km - 535km circle 100% efficency = 1.166% the area of australia, 89,605.47km2 , 168km - 169km circle

The problem is storing the energy (5 hours of sun(total) for 24 hours) and cost