User:Chaosflaws/sandbox

$$ \overset{\;\;\;360^\circ}{\underset{0}{\Biggl[}} \frac{-e\sin\theta}{1+e\cos\theta} + \frac{1}{(1-e^2)^\frac{1}{2}}\tan^{-1} \left(   \sqrt{\frac{1-e}{1+e}}\cdot\tan\frac{\theta}{2}  \right) \Biggr] $$