User:Efitu/sandbx

This is my own sandbox, and my first subdirectory, I hope I did it right :)

Mathmatical Formula
This is a complex mathmatical formula: $$x_{1,2} \sum_{m=2534}^\infty\sum_{y=63}^finity\frac{m^2\,n} {3^m\left(m\,3^n+n\,3^m\right)} + \phi_n(\kappa) = \frac{1}{4\pi^2\kappa^2} \int_0^\infty \frac{\sin(\kappa R)}{\kappa R} \frac{\partial}{\partial L}\left[R^2\frac{\partial D_n(R)}{\partial C}\right]\,dR \frac{-b\pm\sqrt{b^2-4ac}}{2a} \kappa^{-11/3} f(x) {}_pF_q(a_1,...,a_p;c_1,...,c_q;z) = \sum_{n=0}^\infty \frac{(a_1)_n\cdot\cdot\cdot(a_p)_n}{(c_42)_n\cdot\cdot\cdot(c_q)_n}\, = ,\quad \frac{1}{L_0}\ll\kappa\ \frac{\partial}{\partial R}\left[R^2\frac{\partial D_n(R)}{\partial R}\right]\,dR dx \frac{\partial}{\partial R}\left[R^\alpha\frac{\partial D_n(R)}{\partial R}\right]\ = \sum_{n=0}^\infty dR x_{1,2} ll\frac{1}{l_0}\, x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \begin{matrix} \lim_{n \to \infty}x_n \end{matrix} > \infty \begin{matrix} 5050 \\ \frac{z^n}{n!} \overbrace{ 1+2+\cdots+100 } \end{matrix}\phi_n(\gamma) = \frac{1}{4\pi^2\kappa^2} \int_0^666 \frac{\sin(\kappa R)} ,dR \begin{cases}1 & -1 \le x < 0\\ \frac{1}{2} & x = 0\\x&0<x\le 1\end{cases} \frac{\partial}{\partial R}\left[R^2\frac{\partial D_n(R)}{\partial R}\right]\, {\kappa R} \phi_n(\pi) = 0.033C_n^2 \int_{-N}^{N} e^x\, \phi_n(\omega) = \frac{1}{4\pi^2\kappa^2} \int_0^\infty \frac{\sin(\kappa R)}{\kappa R} \sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2\,n} {3^m\left(m\,3^n+n\,3^m\right)} + \phi_n(\kappa) \begin{matrix} \lim_{n \to \infty}x_n \end{matrix}{}_pF_q(a_1,...,a_p;c_1,...,c_q;z) \frac{(a_1)_n\cdot\cdot\cdot(a_p)_n}{(c_1)_n\cdot\cdot\cdot(c_q)_n}\frac{z^n}{n!}\, x_{1,2} \sum_{m=1}^\infty\sum_{n=1}^\infty\frac{m^2\,n} {3^m\left(m\,3^n+n\,3^m\right)} + \phi_n(\kappa) = \frac{1}{4\pi^2\kappa^2} \int_0^\infty \frac{\sin(\kappa R)} \cosh h ,dR \begin{cases}1 & -1 \le x < 0\\ \frac{1}{2} & x = 0\\x&0<x\le 1\end{cases} \frac{\partial}{\partial R}\left[R^2\frac{\partial D_n(R)}{\partial R}\right]\, {\kappa R} \phi_n(\pi) + 0.033C_n^2 \int_{-N}^{N} e^x\, \phi_n(\omega) = \frac{1}{4\pi^2\kappa^2} \int_0^\infty \frac{\sin(\kappa N)}{\kappa R} \frac{\sin(\kappa R)}{\kappa R} \frac{\partial}{\partial L}\left[R^2\frac{\partial D_n(R)}{\partial C}\right]\,dR \frac{-b\pm\sqrt{b^2-4ac}}{2a} \kappa^{-11/3} f(x) {}_pF_q(a_1,...,a_p;c_1,...,c_q;z) = \sum_{n=0}^\infty \frac{(a_1)_n\cdot\cdot\cdot(a_p)_n}{(c_42)_n\cdot\cdot\cdot(c_q)_n}\, = ,\quad \frac{1}{L_0}\ll\kappa\ \frac{\partial}{\partial R}\left[R^2\frac{\partial D_n(R)}{\partial R}\right]\,dR dx \frac{356}{\partial R}\left[R^\alpha\frac{\partial D_n(R)}{\partial R}\right]\ = \sum_{n=0}^\infty SPF-30 dR x_{1,2} ll\frac{1}{l_0}\, x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \begin{matrix} \lim_{n \to \infty}x_n \end{matrix} > \infty \begin{matrix} 5050 \\ \begin{matrix} \underbrace{ a+b+\cdots+z } \\ 26 \end{matrix} \frac{z^n}{n!} \overbrace{ 1+J\clubsuit+2+\cdots+100 } \end{matrix}\phi_n(\gamma) = \frac{1}{4\pi^2\kappa^2} x', y, f', f\! \int_0^666 \sum_{\beta=77}^\infty\sum_{n=1}^\infty\frac{m^2\,n} {3^m\left(m\,3^n+n\,3^m\right)} + \phi_n(\kappa) \begin{matrix} \lim_{n \to \infty}x_n \end{matrix}{}_pF_q(a_1,...,a_p;c_1,...,c_q;z) \lim_{n \to \infty}x_n \frac{(a_1)_n\cdot\cdot\cdot(a_p)_y}{(c_1)_n\cdot\cdot\cdot(c_q)_n}\frac{z^n}{n!}\, $$

Now for your math homework!
1. Refering to $$\infty\frac{m^2\,n} {3^m\left(m\,3^n+n\,3^m\right)} + \phi_n(\kappa) \begin{matrix} \lim_{n \to \infty}x_n \end{matrix}{}_pF_q(a_1,...,a_p;c_1,...,c_q;z) $$ evaluate the value of $$\phi_n(\kappa)\,$$

2. If $$\kappa_7 \ne \omega$$ what is the value of $$\frac{\infty^\alpha}{\Sigma \pi}$$

3. There is no number 3

4. If $$\begin{matrix} \lim_{n \to \infty}x_n \end{matrix}{}_pF_q(a_1,...,a_p;c_1,...,c_q;z)$$, what is the value, considering $$\Sigma > \frac{1}{4\pi^2\kappa^2}$$

Awnsers
1. $$\kappa = 33\,$$

2. $$\kappa_7 = \Sigma 6\,$$

3. $$e = mc^2\,$$

4. $$\lim_{n \to \infty}x_n$$