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$$ F_c = \frac{mv^2}{r} $$

$$ A_c = \frac{v^2}{r} $$

$$ G_F = \frac{G \times M_1 \times M_2}{r^2} $$

$$ G_a = \frac{G \times M_1}{r^2} $$

$$ Work = \Delta KE + \Delta U_g + \Delta W_f $$

$$ F \times \Delta x \times \cos \theta = \frac{1}{2}mv^2 + mg \Delta h + \mu F_n \cos \theta \Delta x $$

$$ \Delta KE = \frac{1}{2} mv^2 $$

$$ \Delta U_g = mg \Delta h $$

$$ W_f = \mu mg \sin \theta $$

$$ U_0 + KE_0 = U_1 + KE_1 + W_f $$

$$ U_G = - \frac {GM_em}{r} $$

$$ P = \frac {W}{t} $$

$$ Work = Joules = Nm = \frac {kgm^2}{s^2} $$

$$ Power = Watts = \frac {Nm}{s} = \frac {kgm^2}{s^3} $$

$$ \sin^2 x + \cos^2 x = 1 $$

$$ f(x) = f(a) \times f(b) \Longrightarrow f'(x) = [f'(a) \times f(b)] + [f'(a) \times f(b)]$$

$$ f'(x) = [f'(a) \times f(b)] + [f'(b) \times f(a)] $$

$$ 1 hp = 745.70 Watts $$

$$ a_1 = a_0 - \frac {f(a_0)}{f'(a_0)} $$

Work = Change in Kinetic Energy + Change in Potential Energy + Work of Friction

F(displacement)(change in inclination) = (1/2mv^2) + (mg)(change in height) + (mu)(Force Normal)(cosine theta)(displacement)

Change in Kinetic Energy = (1/2)mv^2

Change in Potential Energy = mg(change in height)

Work of Friction = (mu)(mg)(sin theta)

PE(0) + KE(0) = PE(1) + KE(1) + W(f)

Absolute Gravitational Potential Energy = F(G) = -(GM(e)m(2))/r

Power = Work / Time