User:InquilineKea/Physics

CT:

(a) $$m_2 g = m_1 (\mu _k \cos \theta + g \sin \theta)$$

(b) $$m_2 g = m_1 ((g \sin \theta - \mu _k \cos \theta)) $$

(c) Lower bound: m_1 pulls on m_2 (b) upper bound: m_2 pulls on m_1. (a)

static friction ALWAYS is higher than kinetic friction, so this narrows down the bonds. So...m_2 is between

$$\frac{m_1 (\mu _k \cos \theta + g \sin \theta)}{g}$$ and $$\frac{m_1 ((g \sin \theta - \mu _k \cos \theta)}{g}$$