User:JelloPiranha/Sandbox1

22.
22a. HCl+NaOH→NaCl+H2O $$2.0molHCl\frac{1molNaOH}{1molHCl}=2.0molNaOH$$ limiting reagent: HCl 22b. Zn+2HCl→ZnCl2+H2 $$2.5molZn\frac{2molHCl}{1molZn}=5.0molHCl$$ limiting reagent: Zn 22c. 2Fe(OH)3+2H2SO4→Fe2(SO4)3+6H2O $$6.5molH_2SO_4\frac{2molFe(OH)_3}{3molH_2SO_4}=4.3molFe(OH)_3$$ limiting reagent: Fe(OH)3

25.
25a. Cu+2AgNO3→Cu(NO3)2+2Ag $$2.50molCu\frac{2molAgNO_3}{1molCu}=5.00molAgNO_3$$ limiting reagent: Cu 25b. $$5.50molAgNO_3-2.50molCu\frac{2molAgNO_3}{1molCu}=0.50molAgNO_3$$ 25c. $$2.50molCu\frac{1molCu(NO_3)_2}{1molCu}=2.50molCu(NO_3)_2$$ $$2.50molCu\frac{2molAg}{1molCu}=5.00molAg$$ 25d. $$2.50molCu\frac{1molCu(NO_3)_2}{1molCu}\frac{161gCu(NO_3)_2}{1molCu(NO_3)_2}=403gCu(NO_3)_2$$ $$2.50molCu\frac{2molAg}{1molCu}\frac{108gAg}{1molAg}=540.gAg$$

26.
26a. 3H2SO4+2Al(OH)3→Al2(SO4)3+6H2O $$30.0gH_2SO_4\frac{1molH_2SO_4}{98.1gH_2SO_4}\frac{2molAl(OH)_3}{2molH_2SO_4}\frac{78.0gAl(OH)_3}{1molAl(OH)_3}=15.9gAl(OH)_3$$ limiting reagent: H2SO4 26b. $$25.0gAl(OH)_3-30.0gH_2SO_4\frac{1molH_2SO_4}{98.1gH_2SO_4}\frac{2molAl(OH)_3}{3molH_2SO_4}\frac{78.0gAl(OH)_3}{1molAl(OH)_3}=9.1gAl(OH)_3$$ 26c. $$30.0gH_2SO_4\frac{1molH_2SO_4}{98.1gH_2SO_4}\frac{1molAl_2(SO_4)_3}{3molH_2SO_4}\frac{342gAl_2(SO_4)_3}{1molAl_2(SO_4)_3}=34.9gAl_2(SO_4)_3$$ $$30.0gH_2SO_4\frac{1molH_2SO_4}{98.1gH_2SO_4}\frac{6molH_2O}{3molH_2SO_4}\frac{18.0gH_2O}{1molH_2O}=11.0gH_2O$$

28.
28a. $$\frac{15.0g}{20.0g}\frac{100\%}{1}=75\%$$ 28b. $$(1.0g)(90.0\%)\frac{1}{100\%}=0.90g$$ 28c. $$\frac{4.75g}{5.00g}\frac{100\%}{1}=95\%$$ 28d. $$(3.45g)(48.0\%)\frac{1}{100\%}=1.66g$$

29.
29. PCl3+Cl2→PCl5 $$73.7gPCl_3\frac{1molPCl_3}{138gPCl_3}\frac{1molPCl_5}{1molPCl_3}\frac{209gPCl_5}{1molPCl_5}(83.2\%)\frac{1}{100\%}=92.9gPCl_5$$

30.
30. 4NH3+5O2→4NO+6H2O 2NO+O2→2NO2 3NO2+H2O→2HNO3+NO $$5.00kgNH_3\frac{1000gNH_3}{1kgNH_3}\frac{1molNH_3}{17.0gNH_3}\frac{4molNO}{4molNH_3}(94.0\%)\frac{1}{100\%}*$$ $$\frac{2molNO_2}{2molNO}(94.0\%)\frac{1}{100\%}\frac{2molHNO_3}{3molNO_2}\frac{63.0gHNO_3}{1molHNO_3}(94.0\%)\frac{1}{100}=10300gHNO_3$$