User:Joseph A. Spadaro/Sandbox/Page69

Background colors for tables
I was reviewing this article: 12th Academy Awards. You will notice that the heading titles on the tables have a background that is a golden color. When I looked at the "code" to produce that gold color, I see (in the edit space for the article) the following notation  ! style="background:#EEDD82; width:50%" | Outstanding Production . OK. So far, so good. So, I presume that the gold color is coming from the notation (code) of  style="background:#EEDD82; . So, my question is: how would I (or anyone) know that #EEDD82 is the code to produce the color gold?  And what if I want another color (purple, green, whatever)?  Is there a list somewhere on Wikipedia (or the internet) that gives all of these codes and their corresponding colors?  Thanks.   Joseph A. Spadaro (talk) 17:50, 27 January 2016 (UTC)


 * This page does a reasonable job. There may well be better alternatives. Maproom (talk) 18:21, 27 January 2016 (UTC)
 * This list may also be helpful. It is too big for a single article, so you will have to pick one from the list.-- S Philbrick (Talk)  19:18, 27 January 2016 (UTC)


 * Thanks. Why is it that my color code (EEDD82) is not listed in those articles?  Joseph A. Spadaro (talk) 20:46, 27 January 2016 (UTC)


 * The article lists only commonly used colours. There are too many shades (over sixteen million) to list them all.  Your shade is 238/256 = 93% brightness red (because EE in hexadecimal is 238 in decimal); 221/256 = just over 86% brightness of green (because DD in hex is 221 in decimal); and 130/256 = just under 51% brightness of blue (because 82 in hex is 130 in decimal).
 * As you probably know, when you mix pure 100% red with pure 100% green, you get a bright yellow (#FFFF00), and mixing some blue (the 82 in your code) makes it lighter and more straw/gold coloured, then reducing the brightness of red and green gives your shade. You can play with the colours in the site linked above.    D b f i r s   23:22, 27 January 2016 (UTC)

Thanks, all. Joseph A. Spadaro (talk) 19:59, 28 January 2016 (UTC)