User:Jotomicron/Sandbox

Signature

 * : ~ Jotomicron 20:19, 7 October 2007 (UTC)
 * ~ : ~ Jotomicron 20:19, 7 October 2007 (UTC) 20:19, 7 October 2007 (UTC)
 * : 20:19, 7 October 2007 (UTC)

Ions
$$\textrm{H}_2\textrm{PO}_4^-$$ : dihydrogenophosphate

$$\textrm{HPO}_4^{2-}$$ : hydrogenophosphate

Formulae
$$ \left\{\begin{matrix} \textrm{pH}=\textrm{7,2}+\log\frac{\left[\textrm{H}_2\textrm{PO}_4^-\right]}{\left[\textrm{HPO}_4^{2-}\right]} \\ \left[\textrm{H}_2\textrm{PO}_4^-\right] + \left[\textrm{HPO}_4^{2-}\right] = 0.1 \end{matrix}\right. \Leftrightarrow $$

$$ \textrm{pH}_\textrm{final} = \textrm{7,2}+\log \frac {\left[\textrm{HPO}_4^{2-}\right] - [\textrm{HCl}]} {\left[\textrm{H}_2\textrm{PO}_4^-\right] + [\textrm{HCl}]} $$

$$ \frac {\left[\textrm{HPO}_4^{2-}\right] - [\textrm{HCl}]} {\left[\textrm{H}_2\textrm{PO}_4^-\right] + [\textrm{HCl}]} $$

$$ c=\frac{n}{V}\Leftrightarrow V=\frac{n}{c} $$

$$ \frac{\Delta \textrm{pH}}{\Delta \textrm{T}}=\frac{6.8-6.9}{37-0}=-0.0027\ \textrm{K}^{-1} $$

$$ \frac{\Delta \textrm{pH}}{\Delta \textrm{T}}=\frac{6.8-6.9}{37-0}=-0.0027\ \textrm{K}^{-1} $$