User:JulianJaeger

$$a = b + c $$

$$3a - 2a = 3b - 2b + 3c - 2c $$

$$3a - 3b - 3c = 2a - 2b -2c $$

$$3*(a-b-c) = 2*(a-b-c) $$

$$3 = 2 $$

Its me: JulianJaeger (talk) 20:34, 8 March 2012 (UTC)