User:Kitten Scientist2104/sandbox

Prediction 1; Day 1;

This will be trying to fire a dart and seeing how it might react (without throwing/firing a dart) without thinking about aerodynamics

Lets find the force;

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So 1 newton( the unit of force in the SI system) is the force required to move a 1 kilogram object 3 meters^2

so our dart is twenty grams, it moved 3 meters^2 in 1 second, so it moved at an average velocity of

3 meters^2 a second that is our average velocity. Since this dart is 20 grams it is 50 times less than 1 kilogram.

1 newton in this case is the amount of force required to launch a 20 gram dart 50 meters^2 a second.

Now we need to solve for our acceleration(if you are jumping around I understand why). So acceleration= Vf-Vi/Tf-Ti.

Since our initial. velocity is 0 meters asecond^2 and our final velocity is 3 meters a second^2( I know someone is think there is also slowing down, yes there is but this includes instantaneous velocity

It would be hard to tell if my calculations are correct in the real world) we have 3 meters a second^2/T

now our initial. time is 0 and our final time is 1 we have 3/1 meters a second^2 as our acceleration. so .02x 3 we get .06 Newtons ( this is what I got using our little multiplication thing above "Since this

dart is 20 grams it is 50 times less than 1 kilogram.1 newton in this case is the amount of force required to launch a 20 gram dart 50 meters^2 a second.").

so that's the force.

Equation(s) used to find force;

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1 newton= the force need to launch a 20 gram object 50 meters a second^2

F=ma to check if the equation above worked

a=Vf-Vi/Tf-Ti

V=S/T

Those are the equations I used to find the force we put on the dart

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Time Dilation.

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Prediction 1; Day 2;

we are now back and are ready to find the time dilation. of the dart relative to earth's time

so T1=12/√1-V^2/c^2. So T1 is the time of the moving observer, T2 is the time of the observer who is not moving( In this Case Relative to earth).

So let's say that T2 is 1. Our velocity of course is 3 meters a second^2. So T1= 1/√1-9/90,000,000,000 not that bad. So after doing this we get

that at that velocity we get 1 second for a non moving observer on earth is (you will laugh) 0.99999999995 seconds for the dart on earth. That means

that the dart has traveled into the future(relative to earth) 0.000000000005 wow. That is purely amazing, this is an instant of science being wonderful yet mysterious.

normal but amazing, and complex yet simple. This is one of the many wonders of science. From the diamond plant WASP-26b to subatomic particles