User:LauritzT/sandbox

Welcome
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It is generally a good idea to propose and discuss potentially controversial changes on the talk page of the article, and establish community consensus before making them.

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Thank you. (signature)

Welcome
Hi, and welcome to Wikipedia.

I noticed you recently made some edits to Example that could be considered controversial.

Please remember that Wikipedia is not a place for your own analysis or commentary and that Wikipedia articles must be neutral and represent all major viewpoints.

I have not reverted your edits, but others may do so, since they may violate Wikipedia's policies. Please remember to avoid an edit war (that's repeatedly changing the page back to how you think it should be) – instead, discuss civilly on the talk page to reach consensus. If that fails, you can seek dispute resolution.

By the way, you may find the Introduction or the primer for newcomers useful for learning about contributing to Wikipedia.

Thank you. (signature)

Regarding inline citations
Hello, and thank you for your contributions to Wikipedia.

It would be appreciated if you could use inline citations to reliable sources when adding information to Wikipedia.


 * Readers should be able to verify claims in Wikipedia articles to ensure that they are trustworthy.
 * Editors may remove content without reliable sources if they don't find credible.
 * Facts, allegations, and ideas for which no reliable, published sources exist, should not be added to Wikipedia.

By the way, you may find the introduction to policies and guidelines useful.

Thank you. (signature)

Welcome, note about hotlinking and copyright
Hello, and thank you for your contributions to Wikipedia.

An image should not be hotlinked, but instead:


 * if it is freely licensed or if its copyright has expired, it should uploaded to Wikimedia Commons,
 * if it falls under the non-free content policy, it can be uploaded to Wikipedia, or
 * if it does not fall under the non-free content policy, it should not be used, since using it may be a copyright violation.

Thank you. (signature)

Test
Voluptas officia repudiandae ad laboriosam vel eaque soluta reiciendis. Repellat vel suscipit et enim nulla occaecati. Vel omnis qui suscipit quia porro quia id repellendus. Delectus ipsum nisi sint facere. Harum nemo quos in eveniet. Et quod temporibus consectetur et rem incidunt non fuga.

— Lauritz Thomsen (talk) 23:20, 7 August 2020 (UTC)


 * Possimus sit fugiat harum. Natus aut hic tempore dolorem beatae porro. At qui non unde consequatur aspernatur quia. Aliquam consequuntur ut labore fugiat. Est magnam animi labore. Quia velit porro sed aut. — Lauritz Thomsen (talk) 23:20, 7 August 2020 (UTC)

Lorem ipsum.


 * Voluptas officia repudiandae ad laboriosam vel eaque soluta reiciendis — Lauritz Thomsen (talk) 08:17, 2 September 2021 (UTC)
 * Voluptas officia repudiandae ad laboriosam vel eaque soluta reiciendis — Lauritz Thomsen (talk) 08:17, 2 September 2021 (UTC)

Signatures

 * — LauritzT (talk)
 * — LauritzT (talk &middot; notify)
 * — &#123;&#123;re&#124;LauritzT&#125;&#125; (talk)
 * — &#123;&#123;re&#124;LauritzT&#125;&#125; (talk)
 * — &#123;&#123; re &#124;LauritzT&#125;&#125; (talk)

Maybe a preload like can be used with a notify link?
 * mw:Manual:Creating pages with preloaded text

Before
The energy E, frequency v, and wavelength λ of a photon are related by

$$E = h\nu = \frac{hc}{\lambda} = \frac{(4.135\ 667\ 516\times 10^{-15}\,\mathrm{eV{\cdot}s})(299\, 792\, 458\,\mathrm{m/s})}{\lambda}$$

where h is the Planck constant, c is the speed of light. This reduces to $$\begin{align} E\mathrm{(eV)} &=4.135\ 667\ 516\,\text{feVs}\cdot\nu\ \text{(PHz)} \\[4pt] &=\frac{1\ 239.841\ 93\,\text{eV}{\cdot}\text{nm}}{\lambda\ \text{(nm)}}. \end{align}$$ A photon with a wavelength of $532 nm$ (green light) would have an energy of approximately $2.33 eV$. Similarly, $1 eV$ would correspond to an infrared photon of wavelength $1,240 nm$ or frequency $241.8 THz$.

After
The energy E, frequency v, and wavelength λ of a photon are related by

$$E = h\nu = \frac{hc}{\lambda} = \frac{(4.135\, 667\, 516 \times 10^{-15}\,\mathrm{eV{\cdot}s})(299\, 792\, 458\,\mathrm{m/s})}{\lambda}$$

where h is the Planck constant, c is the speed of light. This reduces to $$\begin{align} E\mathrm{(eV)} &=4.135\ 667\ 516\,\text{feVs}\cdot\nu \\[4pt] &=\frac{1\ 239.841\ 93\,\text{eV}{\cdot}\text{nm}}{\lambda}. \end{align}$$ A photon with a wavelength of $532 nm$ (green light) would have an energy of approximately $2.33 eV$. Similarly, $1 eV$ would correspond to an infrared photon of wavelength $1,240 nm$ or frequency $241.8 THz$.