User:Lord Matt/madness

Some Fun with assumed distributions - ignore me

$$f(x) = \sum_{n=0}^ {x-1} 2^n $$

let B = Number of Indexed Backlinks

$$f(x) \approx \sqrt {Backlinks}$$

$$\sqrt {Backlinks} \approx \sum_{n=0}^ {PR-1} 2^n $$

My PR Factor Function M $$M(x,B) = \frac {\sqrt[4] {B}} {x}$$

Exact PR Point function g $$g(x) = \sqrt \frac{f(x)} {x}$$

Logarythmic distence to next g(x+1)

$$D(x) = g(x+1) - g(x)$$

long hand $$D(x) = g(x+1) - g(x) =  \sqrt {\frac{f(x+1)} {x+1}} - \sqrt {\frac{f(x)} {x}}$$

Estimated Percentage of the distence to the next level

$$\frac{D(Pagerank)} {M(Pagerank,Backlinks)} * 100$$

Full Math

$$\frac{\sqrt {\frac{f(Pagerank+1)} {Pagerank+1}} - \sqrt {\frac{f(Pagerank)} {Pagerank}}} {\frac {\sqrt[4] {Backlinks}} {Pagerank}} * 100$$

\sum_{0}^ {PR} 2^n

$$\frac{\sqrt {\frac{\sum_{n=0}^ {PR} 2^n} {Pagerank+1}} - \sqrt {\frac{\sum_{n=0}^ {PR-1} 2^n} {Pagerank}}} {\frac {\sqrt[4] {Backlinks}} {Pagerank}} * 100$$

$$g(x) = \sqrt \frac{f(x)} {PR}$$

$$\sqrt \frac{f(PR)} {PR} - \frac {\sqrt[4] {Backlinks}} {PR}$$

(1 - (4th root of B) / PR)

square root(15 + 16) / 5 = 1.11355287 (4th root of 237) / 4   = 0.980905332 square root(15) / 4    = 0.968245837 (4th root of 237) / 5   = 0.784724265

\left = a_0 + a_1 (x-c) + a_2 (x-c)^2 + a_3 (x-c)^3 + \cdots

