User:MarioBarajasAnguiano

f (x) =c(4x-sx2), 		0 < x <2 c∫_0^2▒〖(4x-2x2)dx=〗 (2cx2-2cx3/3)2⁄0 = 2c(x2-x3/3)2⁄0 =2c(4-8/3) =>   c=3/8

P(1⁄2<x< 3⁄2) 3/4 ∫_(1/2)^(3/2)▒(2x-x2)dx= 3/4  (x2-x3/3)  (3/2)⁄(1/2)=  3/4  [81/24- 5/24]=    19/8

E [ x ] = ¿? 3/4 ∫_0^2▒(2x2-x3) dx =   3/4 ( 2x3/3- x4/5)  2⁄0  =  1

E [ x2 ] = ¿?

3/4 ∫_0^2▒(2x3-x3 )  dx =   3/4  ( x4/2- x5/5)  2⁄0   =    6/5 Var(x) = E [ x2 ] – E [ x ]2 = 6/5- 5/5  =    1/5