User:Math2014

$${2(x-2) \over x^2-1} -{3 \over x+1}=$$

$${2x-4 \over x^2-1} -{3(x-1) \over (x+1)(x-1)}=$$

$${2x-4 \over x^2-1} -{(3x-3) \over (x+1)(x-1)}=$$

$${2x-4-(3x-3) \over (x+1)(x-1)} =$$

$${2x-4-3x+3 \over (x+1)(x-1)} =$$

$${-x-1 \over (x+1)(x-1)} =$$

$${-(x+1) \over (x+1)(x-1)} =$$

$${-1 \over (x-1)} =$$

$${1 \over 1-x}$$