User:Mr splosh

hello world!


 * Team B faced 47.2 overs, so their runrate is $$\frac{267}{47\tfrac{1}{3}} = \frac{267}{\tfrac{142}{3}} = \frac{801}{142} \approx 5.64$$
 * Assuming that Team A and Team B had previously played as in the game in scenario one, the new net run rate for team A would be $$\frac{287+265}{50+ 50}-\frac{243+267}{50+47\tfrac{1}{3}} = \frac{552}{100}-\frac{510}{97\tfrac{1}{3}} \approx 0.28$$