User:Nate 2169/sandbox

Fictional Athletes That I Created
🇯🇵 Takahashita Ichirō (JPN)

Xiang Zhongli

Xi Zhaoming

Moon Ji-su

Kim Seong-gyeong

🇺🇸 William Daniel Smith (USA)

Dan Richard Weatherbottom

🇦🇺 Barry Adam Taylor (AUS)

🇮🇸 Alexander Alexander Alexandersson (ISL)

🇷🇺 Alexandrov Ludomir Vladislavovich (RUS)

Japanese
Konkōmyōsaishōōkyō Ongi

Chūō-ku

ポケットモンスター ・ (Poketto Monsutā Rubī-Safaia) (List of Pokémon manga)

ポケットモンスター ・ (Poketto Monsutā Daiyamondo-Pāru)

ポケットモンスター ジョウの (Poketto Monsutā Hātogōrudo Sourushirubā: Jō no Dai Bōken)

ポケットモンスター ・　(Poketto Monsutā Burakku-Howaito)

ポケットモンスター ・ グッドパートナーズ　(Poketto Monsutā Burakku-Howaito: Guddo Pātonāzu)

923は、およびにする、・である.

はにある. のからは32はなれている.

このはのです.

My "Haiku"
は コロナウイルス は

Math
$$x(x+1)(x+2)(x+3)=x(x+1)(x+2)(x+3)(x+4), \text{ } x_{1}=-3, \text{ } x_{2}=-2, \text{ } x_{3}=-1, \text{ } x_{4}=0$$

$$(x+3)(x-3)=x^{2}-9$$

$$\begin{align} \sqrt{\frac{1}{x}}&=\frac{1}{\sqrt{x}} \\ &=\frac{1}{\sqrt{x}}*\frac{\sqrt{x}}{\sqrt{x}} \\ &=\frac{\sqrt{x}}{x} \\ \end{align}$$

$$m=\frac{y_2-y_1}{x_2-x_1}$$

$$\text{Probability of a bomb being in a specific square in Minesweeper}=\frac{\text{Number of bomb arrangements with a bomb in a specific square}}{\text{Total number of possible bomb arrangements in the remaining squares}}$$

$$1+\sqrt{2+\sqrt{3+\sqrt{4+\sqrt{5+\sqrt{6+\sqrt{7+\sqrt{8+\sqrt{9+...}}}}}}}}$$

$$\frac{1}{1+\frac{2}{1+\frac{3}{1+...}}}$$

$$\frac{1}{\frac{2}{\frac{3}{\frac{4}{\frac{5}{\frac{6}{\frac{7}{\frac{8}{\frac{9}{10}}}}}}}}}$$

$$\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}$$

$$\begin{align} \sqrt{126}&=\sqrt{3*42} \\ &=\sqrt{3*3*14} \\ &=3\sqrt{14} \\ \end{align}$$

$$1+\sqrt{2}+\sqrt[3]{3}+\sqrt[4]{4}+...$$

$$\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{1}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}} = 1$$

$$1^{\infty} = 1$$

$$\frac{\frac{\frac{\left(0!+2^{2}+\int_{\int_{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}^{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}d\int_{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}^{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}d_{0}dd_{0}dd}^{\int_{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}^{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}d\int_{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}^{\int_{\int_{0}^{0}d_{3}dd_{3}}^{\int_{0}^{0}d_{3}dd_{3}}d_{2}dd_{2}}d_{0}^{0}dd_{0}dd}\sum_{n=3}^{34}\frac{5}{56}DdD\right)\frac{\left(\frac{\cot\left(\sqrt{\tau}^{2}t\right)}{\frac{d}{dx}\left(2x-x\right)}\cdot\frac{2\cos\left(\frac{\tau}{\pi}\pi t\right)}{\frac{17}{2^{3}+3^{2}}+1^{-35}}\cdot\tan^{2}\left(\frac{\frac{5^{2}-\operatorname{ceil}\left(\pi\right)}{1+2+3+1}}{\frac{3}{2}\cdot\frac{2}{3}\cdot\frac{3}{2}}\sqrt{\pi}\sqrt{\pi}t\right),\frac{\frac{\left(1-\sin^{2}\left(2\pi t\right)\right)}{\frac{\cos\left(2\pi t\right)}{\sin\left(\frac{\pi}{2}\right)}\cdot\frac{\cos\left(\tau\right)}{\frac{\cos\left(0\right)}{\cos\left(2\pi\right)}}}+\left(\sum_{n=1}^{3}\frac{1}{n^{-2}}\right)-2\cdot\frac{\left(3+4\right)}{\frac{\frac{9+2}{2+9}+\frac{1}{1}}{\sqrt{9}-2+1}}}{\sqrt{\frac{1}{2^{-6}}}-\left(\sqrt[4]{81}\cdot\frac{4!}{\left(2+1\right)!}\right)+5}\right)\frac{\frac{-4+\sqrt{4^{2}-4\left(1\right)\left(3\right)}}{2\left(1\right)}}{\frac{-4-\sqrt{4^{2}-4\left(1\right)\left(3\right)}}{2\left(1\right)}}\cdot\frac{\left(\frac{3!}{2!}\cdot\frac{1!}{0!}\right)\cdot0!}{\frac{4!}{5!}\cdot\left(3!-1!\right)}}{\sum_{n=\sum_{n_{2}=1}^{1}n_{2}}^{\sum_{n_{2}=1}^{1^{0^{0^{0^{0^{0^{0}}}}}}}n_{2}}\frac{\frac{\frac{\left(17^{7}-41\cdot10^{7}-7\cdot36^{3}-5\cdot7^{4}-\frac{8^{2}}{2^{1}}-7\cdot7+7\right)}{15^{5}-759373}}{\frac{\frac{\left(11111-1111+111-11+1\right)}{10^{\left(1+1+1+1\right)}+10^{\left(1+1\right)}+10^{0}}}{1+1-1+1-1+-1--1-1--1}}2n}{\sqrt{\frac{4!}{4+\sqrt{2^{\sqrt{4}}}}}}\sum_{n_{3}=\sum_{n_{2}=1}^{1}n_{2}}^{\sum_{n_{2}=1}^{\frac{\frac{\frac{1}{\frac{2}{2}}}{1}+1}{1+\frac{1}{1}}}n_{2}}n_{3}^{\frac{\left(\sum_{n_{0}=\sum_{n_{2}=1}^{1}n_{2}}^{\sum_{n_{2}=1}^{1}n_{2}}n_{0}\sum_{n_{4}=\sum_{n_{2}=1}^{1}n_{2}}^{\sum_{n_{2}=1}^{1}n_{2}}n_{4}-\left(\sum_{n_{0}=\sum_{n_{2}=1}^{1}n_{2}}^{\sum_{n_{2}=1}^{1}n_{2}}n_{0}\sum_{n_{4}=\sum_{n_{2}=1}^{1}n_{2}}^{\sum_{n_{2}=1}^{1}n_{2}}n_{4}\right)\right)}{5555555555555}}-\frac{\frac{0^{0^{0^{0}}}0^{0^{0}}\cdot0^{0}\cdot0^{100^{10^{1^{0}}}}}{123\cdot321\cdot10^{5}\cdot0^{0^{0^{0}}}}}{\frac{\frac{7734124}{3379\cdot10^{4}}}{\sqrt{63^{2}}\cdot45}+\frac{\frac{1289-326^{6}}{843369^{-3}}}{1001601}}}\cdot2!!!!!!!}{\frac{\left(\log_{4}\left(\sqrt{2}^{16}\right)-1\right)!-\frac{4+2}{2^{2}+2}}{\frac{\frac{\left(\left(1^{2}+2^{3}+3^{4}+4^{5}\right)-1111\right)}{\frac{8^{9}-8^{7}-7^{6}-2^{26}}{64894063\cdot3}\cdot3^{2}\cdot3^{0}}}{\frac{5}{\frac{5}{\frac{5}{\frac{5}{\frac{5}{\frac{5}{1}}}}}}+\frac{\frac{\frac{8}{3}}{\frac{1+1}{1+1+1}}}{1+1+1+1}-\frac{5}{\frac{5}{\frac{5}{\frac{5}{\frac{5}{\frac{5}{1}}}}}}}}+\frac{\frac{\sqrt{\frac{\tau}{2}}\int_{-1}^{1}\frac{3}{2}x^{2}dx}{\left(\int_{-\infty}^{\infty}e^{-x^{2}}dx\right)}}{\frac{\operatorname{sgn}\left(\left|t\right|+\frac{1}{10^{10}}\right)}{-\operatorname{sgn}\left(-\left|t\right|-\frac{1}{10^{10}}\right)}}-\frac{\frac{\left(\left(\sqrt[3]{4913}-1\right)^{\frac{1}{2}}-\frac{3!}{2!}\right)+\frac{11-3}{5+\sqrt{\frac{18}{2}}}-e^{\frac{1}{\infty}}+\log\left(\frac{4!}{2}-2!\right)-1^{1^{1^{1^{0}}}}}{1234567890-1234567891+234-232+12345-12345+321-321}+\frac{\frac{0+\frac{0}{1}+\frac{0\cdot0}{1\cdot1}}{1+0-1+1}}{1--5-5}}{\frac{\operatorname{floor}\left(\operatorname{distance}\left(\left(\operatorname{distance}\left(\left(0-0,0+0\right),\left(1,1\right)\right)^{2},\operatorname{distance}\left(\left(2^{2}-1^{1},3\right),\left(2^{2}+1^{2},3\right)\right)\right),\left(2\operatorname{floor}\left(e\right),\sqrt{\operatorname{ceil}\left(\pi\right)}\right)\right)\right)}{\frac{\operatorname{ceil}\left(\operatorname{distance}\left(\left(\operatorname{distance}\left(\left(2^{2}-1^{1},3\right),\left(2^{2}+1^{2},3\right)\right),\operatorname{distance}\left(\left(\frac{7}{3+4},\frac{1}{\frac{1}{0}}\right),\left(0,1^{569}\right)\right)^{2}\right),\left(\operatorname{floor}\left(\frac{\tau}{2}\right),\sqrt{2^{\operatorname{ceil}\left(\sqrt{2}\right)}}\right)\right)\right)}{111111111111111111111111111111111111111111111111111111111111111111111111111\cdot\left(1-1\right)+1}}}+\left(\prod_{k=\sum_{m=0}^{5}4}^{1}k\int_{12}^{-12}\frac{x}{2}dx\right)\cdot\frac{\frac{\frac{\frac{\sin\left(\pi\right)}{\left|\cos\left(\pi\right)\right|}}{\sin\left(\frac{\pi}{2}\right)}}{\frac{\tan\left(0\right)}{\cot\left(1\right)}!}}{\frac{\frac{\frac{\tan\left(0\cdot0\right)}{\cot\left(111\right)}}{\frac{\sinh^{-1}\left(\left|1\right|\right)}{\cosh\left(\pi\right)}}}{\frac{\tan^{-1}\left(1\right)}{192.4512}}!}+\frac{\frac{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}+\frac{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}}{\frac{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}+\frac{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}{\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}+\frac{\frac{1}{1}+\frac{1}{1}}{\frac{1}{1}+\frac{1}{1}}}}-\frac{\frac{\frac{1}{1}}{\frac{\frac{\frac{1}{1}}{\frac{1}{1}}}{\frac{1}{1}}}}{\frac{\frac{\frac{1}{1}}{\frac{1}{1}}}{\frac{1}{\frac{1}{\frac{1}{1}}}}}}}{\left\{\left(34^{2}-12^{3}\right)\cdot\frac{2^{6}}{3!!}+23\cdot3>\sqrt{6!}-\sqrt{3}+\ln\left(45e\right)-\frac{13}{2-1}:1,0\right\}\left|\frac{\frac{\left(\left|\left(\left|-\left(\left|\frac{-3}{\left|-3\right|}\right|\right)\right|\right)\right|\right)}{3+3}}{\frac{\left(\left|\left(\left|-\left(\left|\frac{-6}{\left|-6\right|}\right|\right)\right|\right)\right|\right)}{6+6}}\frac{\sqrt{1-\tan^{2}\left(0\right)}}{\frac{\sqrt{\left(1-\sin^{2}\left(0\right)\right)}}{\sqrt{\left(1-\cos^{2}\left(0\right)\right)}}}+\frac{\operatorname{floor}\left(\log\left(e^{5}\right)\right)\cdot\operatorname{ceil}\left(\frac{1+\sqrt{5}}{2}\right)}{\sqrt{\sqrt{\frac{\ln\left(\ln\left(e^{e}\right)\right)}{\log\left(\log\left(10^{10}\right)\right)}+\frac{\frac{3^{2}+3!}{2\left(5^{2}+1\right)-1}}{\frac{\sqrt{45\cdot5}}{\sqrt{26\cdot100+1}}}}}^{2^{2}}}\frac{\frac{\operatorname{nPr}\left(3^{2}+\sqrt{2^{2}},6^{2}-5^{2}-3^{2}\right)-\operatorname{nPr}\left(5^{3}-5!,2\right)}{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{9\cdot5-\left(5+6\right)\cdot4}}}}}}}}}-\frac{1}{2}}}{\operatorname{nPr}\left(\log\left(\log\left(10^{\left(\ln\left(e^{5}\right)\cdot3-5\right)}\right)^{10}\right),\operatorname{gcf}\left(18,4\right)\right)}\cdot\frac{\left(\operatorname{nCr}\left(3^{2^{1}},2^{2^{1}}\right)-\frac{3!}{\frac{\left(\frac{1}{\infty^{\infty^{\infty}}}+\infty^{-\infty}\right)}{\infty\cdot\infty^{\infty}+\infty!}^{0^{\left(\frac{1}{\infty}\right)!}}}\right)}{4\operatorname{nPr}\left(3!,\frac{5!\left(\operatorname{lcm}\left(18,21\right)-5^{3}\right)}{6^{2}+2^{2}}\right)}+\operatorname{floor}\left(e^{i\pi}+1\operatorname{with}i=-\sqrt{1}\right)\right|}}{\left\{\left\{\right\}=\frac{\left\{\right\}}{\left\{\right\}}+\frac{\left\{\right\}}{\left\{\right\}}\cdot\left\{\right\}:\left\{\right\},\frac{\frac{\left\{\right\}}{\left\{\right\}}}{\left\{\right\}}\right\}+\frac{\tau-\pi}{\pi}-\frac{d}{dx}x+\int_{\frac{d}{dx}x}^{\frac{d}{dy}y}\frac{d}{dz}zdz+\left|1\right|--\left|\frac{1}{1}\right|-\left|\frac{\frac{1}{1}}{\frac{1}{1}}\right|-\frac{\left|\frac{\frac{1}{1}}{\frac{1}{1}}\right|}{\left|\frac{\frac{1}{1}}{\frac{1}{1}}\right|}--\frac{\left|\frac{\frac{1}{1}}{\frac{1}{1}}\right|}{\left|\frac{\frac{1}{1}}{\frac{1}{1}}\right|}-\left|\frac{\frac{1}{1}}{\frac{1}{1}}\right|-\left|\frac{1}{1}\right|--\left|1\right|+\frac{\operatorname{total}\left(\left[1...45\right]\right)}{\sum_{n=1}^{45}n}\cdot\frac{\sum_{n=0}^{44}\left(n+1\right)}{\operatorname{total}\left(\left[45...1\right]\right)}-0^{0}}$$

Ignore this section
Kaghwahwa

Quotes
"Furthermore, this book could not be possible without the wit and charm of those located in an eastern pacific region of semi-autonomous nation-states. You know who you are." -D.L. Nighly

Timeline of Delegate of The East Pacific on NationStates
There have been 34 delegates if you count repeats, and 17 delegates if you do not count repeats.

Timeline
So far, there have been 9 Leaders of the Greatest Republic of Kanria.

Notes:
 * Kanria didn’t exist until January 5, 2018 and the first leader started on May 19, 2018.
 * The ninth leader is Tanya Shongwe Karsprintian, but her name got cut off due to how long it is.

Timeline
So far, there have been 2 Speakers of the House of Representatives of the Greatest Republic of Kanria.

Digraphs
My conlang's digraphs are, in alphabetical order:
 * ⟨ch⟩, pronounced, as in English China.
 * ⟨dh⟩, pronounced, as in English then.
 * ⟨ng⟩, pronounced, as in English swimming.
 * ⟨sh⟩, pronounced, as in English English.
 * ⟨th⟩, pronounced, as in English thin.
 * ⟨zh⟩, pronounced, as in English vision.