User:Nukeh/Sandbox

KE = PE = ¼ ρ g a², so E = ½ ρ g a²

$$x^2$$

\text{PseudoInverse}[\text{dict}]=\alpha ^{1-\text{word}} \text{dict}^{\unicode{F3C7}}-\frac{\alpha ^{-\text{word}} (\text{word}-1)}{\text{word}}