User:Paavono

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$$F_y-\frac{F_t}{2}=sin(\alpha) \cdot F_{elastik}=3290 N$$

$$F_{elastik}=\frac{F_y-F_t}{sin(\alpha)}=\frac{3290-\frac{-140 kg \cdot 9.82 \frac{m}{s^2}}{2}}{sin(71^\circ)}=4.2 kN$$

$$F_{frik}=78.4 \cdot 10^3 N - sin(28^\circ) \cdot 9200 kg \cdot 9.82 \frac{m}{s^2} = 36 kN$$

$$\mu = \frac{F_{frik}}{cos(\alpha)mg}=\frac{36 \cdot 10^3 N}{cos(28^\circ) \cdot 9200 kg \cdot 9.82 \frac{m}{s^2}}=0.45$$