User:Parha/sandbox

$$ \sqrt{2} $$ 근사값 계산하기 (Newton 알고리듬으로)

 * $$x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}$$
 * $$f(x_n)= x_n^2 $$


 * $$f'(x_n)= 2x_n $$