User:Pfafrich/Blahtex/$ bugs

User:Pfafrich/Blahtex en.wikipedia fixup

This page is part a set of pages devoted to fixing latex bugs in the english wikipedia so that they will be compatable with the Blahtex MathML project.

Below are pages which contain the character $ inside a math tag. Each occurence should be replaced by \$ and when fixed the pages should be moved to the done section. Feel free to fix as necessary.

Done

 * Expected value - $$\left( -\$1 \times \frac{37}{38} \right) + \left( \$35 \times \frac{1}{38} \right),$$
 * Factorial - $$n\$\equiv \begin{matrix} \underbrace{ n!^{{n!}^{{\cdot}^{{\cdot}^{{\cdot}^{n!}}}}}} \\ n! \end{matrix} \,$$
 * Factorial - $$n\$=n^{(4)}n \,$$
 * Factorial - $$n\$=(n!)\uparrow\uparrow(n!) \,$$
 * Factorial - $$1\$=1 \,$$
 * Factorial - $$2\$=2^2=4 \,$$
 * Factorial - $$3\$=6\uparrow\uparrow6=6^{6^{6^{6^{6^6}}}} \!$$
 * Incandescent light bulb - $$\left( 60 \ watts \right) \times \left( 8000 \ hours \right) \times \left( \frac{\$ 0.10}{1000 \ watt \cdot hours} \right) = \$48 $$
 * Incandescent light bulb - $$\left( 15 \ watts \right) \times \left( 8000 \ hours \right) \times \left( \frac{\$ 0.10}{1000 \ watt \cdot hours} \right) = \$12 $$
 * Time value of money - $$F \ = \ P \times (F/P) \ = \ P \times (1 + r )^n \ = \ \$100 \times {(1+0.05)^1}=\ \$105$$
 * Time value of money - $$A \ = \ P \times \left( A / P \right)  \ = \ P \times {  r (1+r)^n  \over (1+r)^n - 1   }   \ = \ \$200,000 \times { 0.005(1.005)^{360}  \over (1.005)^{360} - 1 } $$
 * Time value of money - $$= \ \$200,000 \times 0.006 \ = \ \$1,200 {\rm \ per \ month} $$
 * Risk aversion - $$(\$50-\$40)/\$40$$
 * Exponential growth - $$\$1\times(1+0.05)^1=\$1.05$$
 * Exponential growth - $$\$1\times(1+0.05)^{10}=\$1.62$$
 * Exponential growth - $$\$1\times(1+0.05)=\$1.05$$
 * Talk:Economy of Russia - $$\frac{\mbox{GDP - purchasing power parity}}{\mbox{population}} = \frac{620.3 \mbox{ billion } \$}{145470197 \mbox{ people}} = 4264\$ \neq 7700\$$$
 * Talk:Interest - $$I = \$1000 \cdot e^{0.1 \cdot 1} = \$1105.17$$
 * Depreciation - $${Previous\ period's\ NBV} \times {factor \over N} = \$17000 \times {2 \over 5} = \$6800$$
 * Depreciation - $$NBV_1 = \$17000 - \$6800 = \$10200$$
 * Depreciation - $$\$10200 \times {2 \over 5} = \$4080$$
 * Interest parity condition - $$i_\$ = i_D + \frac {e_\$^e - e_\$} {e_\$} (1 + i_D) $$
 * Interest parity condition - $$i_\$ $$
 * Interest parity condition - $$e_\$^e $$
 * Interest parity condition - $$e_\$ $$
 * Interest parity condition - $$\mathbf { }(1 + i_\$) = (F/S)(1 + i_c) $$
 * Interest parity condition - $$(1 + i_\$) < (F/S)(1 + i_c) $$
 * Interest parity condition - $$i_\$ = i_D + \frac {e_\$^e - e_\$} {e_\$} $$
 * Interest parity condition - $$\mathbf { }(1 + i_\$) = (F/S)(1 + i_c) $$
 * Returns to scale - $$\left ( \frac{1000}{100} \right ) = \$10 $$
 * Returns to scale - $$\left ( \frac{1000}{200} \right ) = \$5 $$
 * Cash on cash return - $$\frac{\$\ \mbox{60,000}}{\$\ \mbox{300,000}}=0.20=20\%$$
 * Point in a mortgage - $$\frac{1.5}{100}\times\$100,000=\$1,500$$

Undone

 * Talk:Elon Peace Plan - $$2.3*10^{11}\$$$
 * Talk:Burusera - $$\ 5\$(new\ panties) + 100\$(prostitute)=105\$(pantie\ with\ prostitutively\ enhanced\ odour) > 100\$ (burusera\ pantie) $$
 * User:Egil530/matematikk - $$6,98 \; \$/ounce\,$$
 * User:Plutor/Carrying change - $$\begin{matrix} \mathbb{D} &amp; = &amp; \frac{2.5g}{\$0.01} \\ \ &amp; = &amp; 250\;g/\$ \\ \ &amp; \approx &amp; 0.551\;lb/\$ \end{matrix} $$
 * User:Plutor/Carrying change - $$\begin{matrix} \mathbb{E} &amp; = &amp; \mathbb{D} * \frac{2.7\;mi}{2\;mph} * \frac{1\;cal}{lb * hr} \\ \ &amp; = &amp; \mathbb{D} * 1.35\;cal/lb \\ \ &amp; \approx &amp; 0.744\;cal/\$ \end{matrix} $$
 * Reference desk archive/August 2005 III - $$A_p=\$100,000$$
 * Reference desk archive/August 2005 III - $$R\approx\$804.62$$
 * Reference desk archive/August 2005 III - $$\mathit{R=\$1,685.39}$$
 * Reference desk archive/Science/September 2005 - $$\approx-\$1.24$$
 * Reference desk archive/Science/September 2005 - $$E =\frac{10^6}{720}-\frac{719}{720}\approx\$1,387.89$$
 * Reference desk archive/Science/September 2005 - $$E=(10^6-1)\frac{1}{P(10^6,6)}+(-1)(1-\frac{1}{P(10^6,6)})=-\$1$$
 * User:Tcwd/Math - $$\$500 \times {4\% \over 2}\,$$
 * User:Omegatron/monobook.js/mathcharacterfixer.js -