User:RJFJR/Sandbox

Nyquist plot

Given the Laplace of the transfer function H(s) we evaluate it at H(jω)

If R(ω) is the real part and X(ω) is the imaginary part then A(ω) is the amplitude and φ(ω) is the phase

H(jω)= R(ω) + jI(ω) = A(ω) e jφ(ω)

For the Nyquist plot A(ω) vs φ(ω) for ω from - inf to +inf.

H(-jω)=H*(jω)

notes I left at user talk:omegatron

I dug out my old textbook. Seems that given the transfer function in Laplace form H(s) you evaluate for H(jω) and convert to magnituded and phase H(jω) =A(ω) e j φ(ω) and plot A(ω) vs φ(ω) on polar paper for the Nyquist plot. You need to label points along the curve with the ω but you can display the whole -inf< ω < inf on one page. I don't remember using these either, we did a bunch of Bode phase plots though. Can you just take the data you used for the Bode Phase plot and change it to polar graphing? RJFJR 23:55, 21 October 2005 (UTC)

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