User:Sbussard@nmsu.edu

$$ ma_z=\frac{\rho A {v_{rel}}^2 C_A}{2} $$

$$ \rho = \frac{2ma_z}{A v_{rel}^2 C_A} $$

save the stuff below:

$$ \left \{ \begin{array}{l} \frac{dx}{dt}=x(1-x)+axy=0 \\ \frac{dy}{dt}=y(1-y)+bxy=0 \\ \end{array} \right. $$

$$ \left \{ \begin{array}{l} \frac{dx}{dt}=x(1-x)+axy \\ \frac{dy}{dt}=y(1-y)+bxy \\ \end{array} \right. $$

$$x(1-x)+axy=0$$

$$x(1-x+ay)=0 $$

$$x=ay+1 $$

$$y(1-y)+bxy=0 $$

$$y(1-y+bx)=0 $$

$$y=bx+1 $$

$$x=a(bx+1)+1 $$

$$x=abx+a+1 $$

$$x(1-ab)=a+1$$

$$x=\frac{a+1}{1-ab}$$

$$y=b(ay+1)+1 $$

$$y=aby+b+1$$

$$y(1-ab)=b+1 $$

$$y=\frac{b+1}{1-ab}$$