User:Sean Whitton/Sandbox 2

Sean's formula sheet
Things that I don't quite know off by heart or don't know as well as I should do for A-level are here. Old things fixed in my mind are not. {| cellpadding="50" width="100%" class="wikitable" style="text-align: center;" (x - x_1) = m(y - y_1) $$ v = u + at $$ s = ut + \tfrac{1}{2}at^2 $$ v^2 = u^2 + 2as $$
 * colspan="2" | Equation of a straight line
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 * Will quickly arrive at $$y = mx + c$$, where $$(x_1, y_1)$$ is a point on the line in question.
 * colspan="2" | Equations of uniformally accelerated motion
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 * When $$s$$ is not involved
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 * When $$v$$ is not involved
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 * Thunderbird Two

When $$t$$ is not involved s = \tfrac{1}{2}(v + u)t $$
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$$ s = \frac{(u + v)t}{2} $$
 * When $$a$$ is not involved
 * colspan="2" style="background-color: white; padding: 20px;" | Being fancy:
 * colspan="2" style="background-color: white; padding: 20px;" | Being fancy:

$$\,x_f - x_i = v_i t + \tfrac{1}{2} at^2 \qquad x_f - x_i = \tfrac{1}{2} (v_f + v_i)t$$ $$\,v_f = v_i + a t \qquad v_f^2 = v_i^2 + 2 a (x_f - x_i)$$ P(A') = 1 - P(A) $$ P(A \cup B) = P(A) + P(B) - P(A \cap B) $$ P(A \cap B) = P(A) + P(B) - P(A \cup B) $$ P(A|B) = \frac{P(A \cap B)}{P(B)} $$ \mbox{Fill in the better method here.} $$ \mbox{or}\ P(A|B) = P(A)P(B)\ \mbox{per tree diagram} $$
 * colspan="2" | Formulae for non-independent events in probability
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 * The probability of an event not occuring is 1 minus the event's probability; this is always true regardless of dependence.
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 * Union means that the events occur together? Ack.
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 * Rearrangement of the above - intersection is that both the events occur?
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 * Given that B has occurred, this is the probability A will occur.
 * colspan="2" | Deciding if an event is independent
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